Answer is: <span>the molarity of the diluted solution 0,454 M.
</span>V₁(NaOH) = 100 mL ÷ 1000 mL/L = 0,1 L.
c₁(NaOH) = 0,75 M = 0,75 mol/L.
n₁(NaOH) = c₁(NaOH) · V₁(NaOH).
n₁(NaOH) = 0,75 mol/L · 0,1 L.
n₁(NaOH) = 0,075 mol
n₂(NaOH) = n₁(NaOH) = 0,075 mol.
V₂(NaOH) = 165 mL ÷ 1000 mL/L = 0,165 L.
c₂(NaOH) = n₂(NaOH) ÷ V₂(NaOH).
c₂(NaOH) = 0,075 mol ÷ 0,165 L.
c₂(NaOH) = 0,454 mol/L.
<u>Answer:</u>
The percentage of honey in one granola bar is 26.02 percent.
<u>Explanation:</u>
The weight of 1 granola bar is 42.9 grams. The grams of honey that is present in one granola bar is equal to 26.02 percent of 42.9 = 11.16 g
Now the amount of honey in the factory is given as 189.5g the weight of total granola bars would be

So no. of granula bars
that can be Approximated to nearly 17
Now if one box has 6 bars then 17 bars will have to fit inside three boxes
Answer:
i think so 1 and 3 is the correct answer...................