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Rama09 [41]
3 years ago
11

An acid and a base solution were mixed together in a crucible and all the water in the mixture was evaporated off. What is left

in the crucible?
Chemistry
1 answer:
Ratling [72]3 years ago
5 0

Answer:

Base on the question , an acid and  a base solution was mixed together in a crucible and all the water in the mixture was evaporated off. The only substance left in the crucible is the salt solution.

Explanation:

Acids are substances that dissolves in water to produce hydrogen ion(H⁺) while base are substances that dissolves in water to produce hydroxide ion (OH⁻).

The chemical reaction between an acid and a base solution is known as a neutralization reaction. The reaction between these 2 compounds will produce salt and water.  An acid solution will react with a base solution to form salt and water.  An example of this kind of reaction is between HCl (Hydrochloric acid) and NaOH(sodium hydroxide).

HCl + NaOH → NaCl + H₂O . The product form here is sodium chloride(salt) and water

Base on the question , an acid and  a base solution was mixed together in a crucible and all the water in the mixture was evaporated off. The only substance left in the crucible is the salt solution. Note that the other product which is water has been evaporated and we are left with only salt solution.

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What is the concentration of 10.00mL of HBr if it takes 16.73 mL of a 0.253M LiOH solution to neutralize it?
Fudgin [204]
The chemical reaction would be expressed as follows:

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We are given the volumes and corresponding concentration to be used for the reaction. We use these values to solve for the concentration of the other reactant. We do as follows:

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The radioactive substance cesium-137 has a half-life of 30 years. The amount At (in grams) of a sample of cesium-137 remaining a
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A_t(t)=458\times (\frac{1}{2})^{\frac{t}{30}

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Putting values in above equation:

A_t(t)=458\times (\frac{1}{2})^{\frac{20}{30}

A_t(t)=288.522g

Hence, the amount of sample left after 20 years is 288.522 g

  • <u>For t = 50 years</u>

Putting values in above equation:

A_t(t)=458\times (\frac{1}{2})^{\frac{50}{30}

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