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Rama09 [41]
3 years ago
11

An acid and a base solution were mixed together in a crucible and all the water in the mixture was evaporated off. What is left

in the crucible?
Chemistry
1 answer:
Ratling [72]3 years ago
5 0

Answer:

Base on the question , an acid and  a base solution was mixed together in a crucible and all the water in the mixture was evaporated off. The only substance left in the crucible is the salt solution.

Explanation:

Acids are substances that dissolves in water to produce hydrogen ion(H⁺) while base are substances that dissolves in water to produce hydroxide ion (OH⁻).

The chemical reaction between an acid and a base solution is known as a neutralization reaction. The reaction between these 2 compounds will produce salt and water.  An acid solution will react with a base solution to form salt and water.  An example of this kind of reaction is between HCl (Hydrochloric acid) and NaOH(sodium hydroxide).

HCl + NaOH → NaCl + H₂O . The product form here is sodium chloride(salt) and water

Base on the question , an acid and  a base solution was mixed together in a crucible and all the water in the mixture was evaporated off. The only substance left in the crucible is the salt solution. Note that the other product which is water has been evaporated and we are left with only salt solution.

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All mixtures contain only one kind of atom.

~Mschmindy

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3 years ago
If the particles of matter that make up a substance are relatively far apart and can move freely, the substance is in what state
Novay_Z [31]

Answer:

Gaseous

Explanation:

Gasses can move freely and do not form the shape of their containers

Liquids are more free than solids, but they conform to the shape of their container

Solids are not free

5 0
3 years ago
A chemist adds of a calcium sulfate solution to a reaction flask. Calculate the mass in grams of calcium sulfate the chemist has
Elanso [62]

The given question is incomplete. The complete question is:

A chemist adds 0.85 L of a 0.0050M calcium sulfate to a reaction flask. Calculate the mass in grams of calcium sulfate the chemist has added to the flask. Round your answer to significant digits.

Answer: The mass in grams of calcium sulfate the chemist has added to the flask is 0.58 g

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n}{V_s}

where,

n = moles of solute

V_s = volume of solution in L

moles of CaSO_4 = \frac{\text {given mass}}{\text {Molar mass}}=\frac{xg}{136g/mol}

Now put all the given values in the formula of molarity, we get

0.0050=\frac{x}{136\times 0.85}

x=0.58 g

Therefore, the mass in grams of calcium sulfate the chemist has added to the flask is 0.58 g

7 0
3 years ago
The principal that states that an object at rest will stay at rest and that an object in motion will stay in motion is the law o
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Answer: <em>Newton's first law</em>

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6 0
3 years ago
Read 2 more answers
The complete orbital notation diagram of an atom is shown.
Yuki888 [10]

Answer:

Explanation:

From the description provided by the statement of the problem, we can easily solve for the values of the angular momentum quantum number.

Let us represent the atom as J:

In atom J, we have five sub-orbitals in which there 9 electrons. From the designation used to represent sublevels, we can write the notation as below:

             J = 10 electrons = 1s² 2s² 2p⁵

The s-sublevel can only contain 2 electrons

p-sublevel can contain 6 electrons but we have just 5 electrons in there.

Now, to find the angular momentum quantum number, we need to understand what this quantum number denotes.

This quantum number is also known as azimuthal or secondary quantum number. It gives the shape of the orbitals in subshells accomodating electrons. This quantum number is designated by (l).

         l (n-1)            name of orbital               shape of orbital

             0                     s                                   spherical

             1                     p                                    dumb-bell

             2                    d                                    double dumb-bell

             3                    f                                      complex

J  = 1s² 2s² 2p⁵

where 1 and 2 coefficients are the principal quantum numbers(n).

            s and p are the shape of the orbitals

For 1s², the l vaue is 0 because the electron is in the s orbital

     2s² the l value is 0, 1 and the electron can be in the s or p orbitals

     2p⁵ the l value is 0, 1 and the electrons can be in the s or p orbitals

The quantum number gives the shape of the orbital.

8 0
3 years ago
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