All categories

2 years ago

What is the molarity of a 9.0 L solution that contains 0.500 mol HCl?

Chemistry

1 answer:

victus00 [196]2 years ago

6 0

Answer: 0.056

Explanation:

You might be interested in

What is the mass of a 5.00 cm^3 piece of copper having a density of 8.96 g/cm^3

erik [133]

Answer:

44.8 g

Explanation:

Density = mass / Volume

Mass = density x Volume = 8.96x 5 = 44.8 g

5 0

3 years ago

What is a pure substance - bread, salt, seawater, or soil?

miv72 [106K]

Answer:

Salt is the pure substance out of them all.

5 0

3 years ago

Read 2 more answers

Which of these chemical formulas — Cl2 , KCI, Ar, NO2– represents both an element and a molecule ?

Tasya [4]

The answer is: Cl2.

Chlorine is diatomic molecule made of two chlorine atoms.

Diatomic molecules are molecules made of two atoms.

They can be homonuclear (molecule made of two atoms of the same element) and heteronuclear (molecule made of two different atoms).

Chlorine (Cl) is halogen element.

Halogen elements are in group 17: fluorine (F), chlorine (Cl), bromine (Br) and iodine (I). They are very reactive and easily form many compounds.

4 0

2 years ago

Read 2 more answers

How many gram of gaseous carbon dioxide can be absorbed or reacted by 2kg of lithium hydroxide?

Greeley [361]

Answer:

shuuuuuuuuuuuuuuuuuuuuuuush

Explanation:

shush suuush shuuush

5 0

3 years ago

A sheet of polyethylene 1.5-mm thick is being used as an oxygen barrier at a temperature of 600K. If the flux is 2.48 x 10-5 kg/

Eddi Din [679]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The concentration of high-pressure side is $C_1 = 0.722 \ kg/m^3$

Explanation:

From the question we are told that

The thickness of the polyethylene is $d = 1.5 \ mm = 0.0015 \ m$

The temperature is $T = 600 \ K$

The flux is $JA = 2.48 *10^{-5} \ kg/m^2\cdot s$

The concentration on the low-pressure side is $C_2 = 0.5 \ kg/m^3$

The initial diffusivity is $D_o = 6.2 *10^{-4} \ m^2 /s$

The activation energy for diffusion is $Q_d = 41 \ kJ /mol = 41*10^3 J /mol$

Generally the diffusivity of the oxygen at 600 K can be mathematically evaluated as

$D = D_o * e^{- \frac{Q_d}{R * T } }$

substituting values

$D = 6.2*10^{-4} * e^{- \frac{41 *10^3}{8.314 * 600 } }$

$D = 1.671 *10^{-7} \ m^2 /s$

Generally the flux is mathematically represented as

$JA = D * \frac{C_1 -C_2}{d}$

Where $C_1$ is the concentration of oxygen at the higher side

$C_1 = d * \frac{JA}{D} + C_2$

substituting values

$C_1 = 0.0015 * \frac{2.48*10^{-5}}{1.671*10^{-7}} + 0.5$

$C_1 = 0.722 \ kg/m^3$

6 0

3 years ago