Answer:
a)
a = 1/5
b = 1/3
b)
x(1/3) = 2.500
y(1/3) = 2.598
c)
x'(t) = -5π sin(π t)
d)
x'(1/3) = -13.603
Explanation:
Hi!
a)
We can notice that
x(t)/5 = cos(πt)
y(t)/3 = sin(πt)
Therefore:
( x(t) / 5 )^2 + ( y(t) / 3 )^2 = cos^2(πt) + sin^2(πt) = 1
That is:
a = 1/5
b = 1/3
b)
At t=1/3
x(1/3) = 5 cos(π/3)
y(1/3) = 3 sin(π/3)
But
cos(π/3) = 1/2 = 0.5
sin(π/3) = √3 / 2 = 0.866
That is:
x(1/3) = 2.5
y(1/3) = 2.598
c)
The horizontal velocity is:
x'(t) = -5π sin(π t)
d)
at time t =1/3
x'(1/3) = -5π sin(π/3) = -13.603
Electrostatic force changes like the inverse square of the distance (just like gravity).
If you double the distance, you change the force to 1/4 of what it used to be.
After the move, Objects 1 and 2 attract each other with a force of (18/16) = 1.125 units .
Answer: A surface wave is a wave that moves along the interface of two different materials, like air and water.
Answer:
Una secadora de cabello tiene una resistencia de 10Ω al circular una corriente de 6 Amperes, si está conectado a una diferencia de potencial de 120 V, durante 18 minutos ¿Qué cantidad de calor produce?, expresado en calorías
Explanation:
Una secadora de cabello tiene una resistencia de 10Ω al circular una corriente de 6 Amperes, si está conectado a una diferencia de potencial de 120 V, durante 18 minutos ¿Qué cantidad de calor produce?, expresado en calorías
Answer:
a. 5 × 10¹⁹ protons b. 2.05 × 10⁷ °C
Explanation:
Here is the complete question
A beam of protons is moving toward a target in a particle accelerator. This beam constitutes a current whose value is 0.42 A. (a) How many protons strike the target in 19 seconds? (b) Each proton has a kinetic energy of 6.0 x 10-12 J. Suppose the target is a 17-gram block of metal whose specific heat capacity is 860 J/(kg Co), and all the kinetic energy of the protons goes into heating it up. What is the change in temperature of the block at the end of 19 s?
Solution
a.
i = Q/t = ne/t
n = it/e where i = current = 0.42 A, n = number of protons, e = proton charge = 1.602 × 10⁻¹⁹ C and t = time = 19 s
So n = 0.42 A × 19 s/1.602 × 10⁻¹⁹ C
= 4.98 × 10¹⁹ protons
≅ 5 × 10¹⁹ protons
b
The total kinetic energy of the protons = heat change of target
total kinetic energy of the protons = n × kinetic energy per proton
= 5 × 10¹⁹ protons × 6.0 × 10⁻¹² J per proton
= 30 × 10⁷ J
heat change of target = Q = mcΔT ⇒ ΔT = Q/mc where m = mass of block = 17 g = 0.017 kg and c = specific heat capacity = 860 J/(kg °C)
ΔT = Q/mc = 30 × 10⁷ J/0.017 kg × 860 J/(kg °C)
= 30 × 10⁷/14.62
= 2.05 × 10⁷ °C
