Answer:
the maximum speed of the ball is 12.65 m/s
Explanation:
Given;
mass of the ball, m = 40 g = 0.04 kg
spring constant, k = 25 N/m
Apply the principle of conservation of energy;
The Elastic potential energy of the spring will be converted into Kinetic of the ball;
Therefore, the maximum speed of the ball is 12.65 m/s
Answer:
Due to energy loss while collision ball will not reach to same height while if there is no energy loss then in that case ball will reach to same height
Explanation:
As we know that initially ball is held at height h = 40 cm
So here we can say that kinetic energy of the ball is zero and potential energy is given as
now when strike with the ground then its its fraction of kinetic energy is lost in form of other energies
So the ball will left rebound with smaller energy and hence it will reach to height less than the initial height
While if we assume that there is no energy loss during collision then in that case ball will reach to same height again