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4 years ago

Identify the neutralization reaction

Chemistry

1 answer:

KIM [24]4 years ago

5 0

In chemistry, neutralization or neutralisation (see spelling differences) is a chemical reaction in which an acid and a base react quantitatively with each other. In a reaction in water, neutralization results in there being no excess of hydrogen or hydroxide ions present in the solution.

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Which of these are ways in which a seed might be dispersed? Check all that apply. organisms clouds wind water rocks

alisha [4.7K]

Answer: organisms

wind

water

Explanation:

There are several ways through which plants can move the seed of plants from one place to another. It isn't possible for plants to move their seeds themselves, therefore, there are other methods for their seeds to be moved.

These include fire, wind, animals, organisms, water, fire, water etc. It should be noted that rocks and clouds are not dispersion methods.

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3 years ago

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2AlBr3 + ___ -> 6KBr + Al2(SO4)3

Masja [62]

Answer:

Explanation:

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3 years ago

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You are given 600 grams of sodium chloride (NaCl), but you are planning to purify the substance and extract just the sodium. How

Eddi Din [679]

Answer:

236.02 grams of Na is produced by 600g of NaCl.

Explanation:

NaCl --> Na+Cl-

to find the number of moles NaCl has, divide the grams over the molar mass which is 600/58.44

number of moles of nacl= 10.2 moles

then turn moles back to grams which is moles x molar mass

10.2 moles x 22.9 mass

= 236.02 grams

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3 years ago

What mass of limestone (in kg) would be required to completely neutralize a 15.5 billion-liter lake that is 1.7×10^−5 M in H2SO4

Alinara [238K]

The complete balanced chemical reactions are:

HNO3 => CaCO3 + 2HNO3 → Ca(NO3)2 + H2O + CO2(g)

H2SO4 => CaCO3 + H2SO4 → CaSO4 + H2O + CO2(g)

So we see that 1 mole of CaCO3 is needed for 2 moles of HNO3 and similarly to 1 mole of H2SO4.
The number of moles can be calculated as the product of volume and molarity, so:

moles H2SO4 = 1.7×10^−5 M * (15.5 x 10^9 L) = 263,500 mol H2SO4

moles HNO3 = 8.9×10^−6 M * (15.5 x 10^9 L) = 137,950 mol HNO3

So the total moles of CaCO3 required is:

moles CaCO3 = 263,500 mol * 1 + 137,950 mol * (1/2)

moles CaCO3 = 332,475 mol

The molar mass of CaCO3 is 100.086 g/mol, so the mass is:

mass CaCO3 = 332,475 mol * 100.086 g/mol

mass CaCO3 = 33,276,092.85 g = 33.3 x 10^3 kg

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4 years ago

These are the photos for part A

Alla [95]

Answer:

Explanation:

For part C, this should be what the graph looks like.

The reactants should have higher energy that the products so that it can release energy. Recall the reaction is N2 + 3H2 => 2NH3 + energy, making it exothermic. Apparently, you are supposed to adjust the energy diagram on the simulation so that 20% of the reactants become the products.

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3 years ago