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slava [35]
3 years ago
9

How many grams of glucose(C6H12O6) are produced by 10.0 grams of water(H2O)?

Chemistry
1 answer:
GaryK [48]3 years ago
3 0

Answer:

16.7 g of glucose

Explanation:

Convert grams of H₂O to moles.  <em>0.555 mol</em>

We can use the chemical equation to determine the theoretical yield.  Based on the equation, for every 6 moles of H₂O, 1 mole of glucose is produced.  The ratio of glucose moles to H₂O moles is 1/6.  

Multiply the moles of H₂O by the ratio to find moles of glucose.  <em>0.0925 mol</em>

Convert moles of glucose to grams.  <em>16.7 g</em>

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Calculate the amount in grams of Na2CO3 needed to react with HCL to produce 120g NaCl
worty [1.4K]
Let's start off with the balanced chemical equation:

Na_2CO_{3_{(s)}} + \textbf2HCl_{_{(aq)}}\rightarrow CO_{2_{(g)}} + H_2O_{_{(l)}} + \textbf2NaCl_{_{(aq)}}

Assuming the sodium carbonate is the limiting reagent, look at the coefficients of sodium carbonate and sodium chloride and use those as a ratio of sodium carbonate to sodium chloride: 1:2.

Since you have the required mass of NaCl, convert this to moles.

Assuming you know how to find the molar mass of NaCl:

M_{NaCl} = 58.44g/mol
n = \frac{m}{M}
n_{NaCl} = \frac{120g}{58.44g/mol}
n_{NaCl} = 2.053mol

Using the ratio, since 1 mole of sodium carbonate is required to produce 2 moles of sodium chloride, cross-multiply the ratios:

1:2 = x:2.053mol
2x = 2.053mol
x = 1.027mol

Therefore 1.027 moles of sodium carbonate is required to produce the required amount of sodium chloride. Convert to mass for your final answer:

n_{Na_2CO_3} = 1.027mol
M_{Na_2CO_3} = 105.99g/mol
m = nM
m = (1.027mol)(105.99g/mol)
m_{Na_2CO_3} = 108.85g

Hope this helps :)
6 0
3 years ago
Write an equation showing how this buffer neutralizes added base (ba(oh2.
Crank
Ba(OH)2 can be neutralized by adding an acid to the solution. We can add HCl to produce:

Ba(OH)2 + 2HCl ===> BaCl2 + 2H2O ; producing a salt BaCl2 and water. 

or we can add H2SO4 to produce:

Ba(OH)2 + H2SO4 ===> BaSO4 + 2H2O; producing a salt, BaSO4, and water. <span />
6 0
3 years ago
____________ are solutions that resist changes in ph when moderate amounts of acids or bases are added and contain ions or molec
Kaylis [27]
<u><em>Buffers</em></u> <span>are solutions that resist changes in ph when moderate amounts of acids or bases are added and contain ions or molecules that react with oh- or h when these ions are introduced into solution.</span>
5 0
3 years ago
What is the mass, in grams, of 28.80 ml of acetone?
oee [108]

density of acetone in gm/cm^3 is 0.791

=28.80cm^3*0.791 g/cm63

=22.78 g

8 0
3 years ago
Read 2 more answers
Mass = 100g, volume=20ml, what is density?
Nonamiya [84]

Answer:

<h3>The answer is 5.0 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 100 g

volume = 20 mL

So we have

density =  \frac{100}{20}  \\

We have the final answer as

<h3>5.0 g/mL</h3>

Hope this helps you

4 0
3 years ago
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