All categories

3 years ago

Klklklkllkllklkklkllkl

Chemistry

1 answer:

Svetradugi [14.3K]3 years ago

5 0

Answer:

klklklkllkllklkklkllkl

Explanation:

Cuz thats what you said.. and why not :)

You might be interested in

levacccp [35]

Answer:

the time required for one half of a sample of a radioisotope to decay

7 0

2 years ago

1. Each bag of flour is 8.9 grams. What is the weight of 4 bag of flour?

Serggg [28]

Answer:

8.9g×4=35.6g

Explanation:

follow please

5 0

3 years ago

Carbon disulfide burns in oxygen to yield carbon dioxide and sulfur dioxide according to the following chemical equation. CS2(l)

Semmy [17]

Answer:

a) the limiting reactant is 02

b) There will remain 0.667 moles of CS2

c) There will be formed 0.333 moles oof CO2 and 0.667 moles of SO2

Explanation:

Step 1: Data given

Number of moles of CS2 = 1.00 mol

Number of moles of O2 = 1.00 mol

Molar mass of O2 = 32 g/mol

Molar mass of CS2 = 76.14 g/mol

Step 2: The balanced equation

CS2(l) + 3O2(g) → CO2(g) + 2SO2(g)

Step 3: Calculate the limiting reactant

For 1 mole of CS2 we need 3 moles of O2 to produce 1 mol of CO2 and 2 moles of SO2

O2 is the limiting reactant. It will completely be consumed.(1.00 mol).

CS2 is in excess. There will react 1.00/ 3 = 0.333 moles

There will remain 1.00 - 0.333 = 0.667 moles of CS2

Step 4: Calculate moles of CO2 and SO2

For 1 mole of CS2 we need 3 moles of O2 to produce 1 mol of CO2 and 2 moles of SO2

For 1.00 mol of O2 we have 1.00/3 = 0.333 moles CO2

For 1.00 mol of O2 we have 1.00 /(3/2) = 0.667 moles of SO2

8 0

3 years ago

To the nearest gram, what is the mass of of one spoonfull of sugar? g

Vaselesa [24]

Answer:

the mass of one spoonful of sugar to nearest gram is 10g

4 0

3 years ago

Ivanshal [37]

Answer:

$HCl conc=2.2M$

Explanation:

From the question we are told that:

Mass of zinc $Mass_{z_n}=2.5g$

Initial conc of HCl $HConc_1=6.0M$

Initial volume of HCl $Hvol_1=20.0mL$

Molar mass of zinc $M_{Z_n}=65.38g/mol$

Generally the equation for reaction is mathematically given by

$2HCL+Zn\implies ZnCl_2 +H_2$

Generally the equation for moles of zinc $m_{z_n}$ is mathematically given by

$m_{z_n}=\frac{Mass_{Z_n}}{M_{Z_n}}$

$m_{z_n}=\frac{2.5g}{M_{65.38}}$

$m_{z_n}=0.038molZn$

Generally the equation for moles of $m_{HCl}$ is mathematically given by

$m_{HCl}=HConc_1*Hvol_1$

$m_{HCl}=6.0M*20.0mL$

$m_{HCl}=6.0M*20.0*10^{-3}L$

$m_{HCl}=0.12\ mol\ HCl$

Generally the reacted moles of HCl $HCl_[reacted]$ is mathematically given by

Since

Zn:HCl =1:2

Therefore

$HCl_[reacted]=0.038*\frac{2}{1}$

$HCl_[reacted]=0.076mol \ HCl$

Generally the moles of HCl after Zn oxidization X is mathematically given by

$x=0.12-0.076$

$x=0.044 mol HCl$

Generally the conc of hydrochloride acid X is mathematically given by

$X=\frac{0.044}{0.020}$

$X=2.2 M Hcl$

Therefore Conc of HCl

$HCl conc=2.2M$

5 0

3 years ago