D. 18 x 10^23 is the total number of atoms in 1.0 mole of CO2
Answer:
85.8 g
Explanation:
The molar mass of BaCl₂ is 208.233 g/mol, so 210.1 g is about ...
210.1/208.233 ≈ 1.009 mol
The molar mass of K is about 39.089 g/mol, so 45 g is about ...
45/39.089 ≈ 1.1509 mol
The balanced equation seems to be ...
BaCl₂ + 2K ↔ 2KCl + Ba
This reaction requires 2 moles of potassium for each mole of barium chloride, so the available potassium limits the reaction. The result is as many moles of potassium chloride as there are moles of potassium.
The 1.1509 moles of KCl, at 74.551 g/mol will have a mass of about 85.8 g.
The reaction produces 85.8 g of KCl.
Answer:
Types of atomic orbitals present in the third principal energy are <u>s, p and d only .</u>
Explanation:
- <u>OPTION A-: s and p atomic orbitals -</u> these two orbitals are present in second principal energy level. Therefore , the option is incorrect.
- <u> OPTION B-: p and d only -</u> This option is wrong as there is no such principal level energy where , s atomic orbital is absent .
- <u>OPTION C-: s , p and d only -</u>these orbitals are present in<u> third principal energy level</u>. The third major level of energy has one orbital, three orbitals of p, and five orbitals of d, each of which can contain up to 10 electrons. The third stage thus holds a maximum of 18 electrons. This option is correct .
- <u>OPTION D-: s , p, d and f only -</u>There is also a f sublevel at the <u>fourth and higher stages,</u> containing seven f orbitals, which can accommodate up to 14 electrons at most. Therefore, up to 32 electrons will hold the fourth level: 2 in the s orbital, 6 in the three p orbitals, 10 in the five d orbitals, and 14 in the seven f orbitals. This option is incorrect .
<u>Thus , the correct option is C (s , p and d only .)</u>
I’m a monkey and so are you I will shove my pp in you
Pretty sure it’s C the added products drives reverse reaction and since forward releases heat, reverse would absorb.