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irinina [24]
4 years ago
13

At 30 C, exactly 95 grams of this salt dissolved completely in 100 grams of water. According to the solubility chart, the salt i

s
Physics
2 answers:
Olenka [21]4 years ago
5 0

Answer:

sodium nitrate

Find 30oC on the X axis first. Find the intersection of 30 on X and 95 on Y. Read the line label; it is sodium nitrate.

Explanation:

MAXImum [283]4 years ago
3 0
<h2>Answer:</h2>

At 30 C, exactly 95 grams of this salt dissolved completely in 100 grams of water. According to the solubility chart, the salt is Sodium niatrate NaNo3

Every single metallic nitrate are inorganic salts of a given metal cation and the nitrate anion. The nitrate anion is a univalent (- 1 charge) poly atomic particle made out of a solitary nitrogen iota ionically bound to three oxygen molecules for an all out equation load of 62.05. Nitrate mixes are commonly solvent in water.


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dimaraw [331]
<h3><u>Answer;</u></h3>

D) Standing wave

<h3><u>Explanation;</u></h3>
  • Standing wave also called stationary wave  is a wave which oscillates in time but whose peak amplitude profile does not move in space.
  • A standing wave pattern is a vibrational pattern created within a medium when the vibrational frequency of the source causes reflected waves from one end of the medium to interfere with incident waves from the source.
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3 years ago
Visible light represents a very small portion of the electromagnetic spectrum. Radiation to the left in the image, such as micro
amid [387]
X rays have a higher frequency so A
4 0
3 years ago
Read 2 more answers
Which of the following statements about price elasticity of demand is​ true?
STatiana [176]

Answer:

B. The elastic portion of a​ straight-line, downward-sloping demand curve corresponds to the segment above the midpoint.

Explanation:

Elasticity measures the sensitivity of one variable to another. Specifically it is a figure that indicates the percentage variation that a variable will experience in response to a variation of another one percent.

The elasticity of demand measures the reaction of demand when one of the factors that affects it varies.

<u>Elasticity - Price of demand.</u>

easure the sensitivity of the quantity demanded to price variations. It indicates the percentage variation that the quantity demanded of a good will experience if its price rises by 1 percent.

<u> Elastic Demand </u>

The demand quantity is relatively sensitive to price variations, so the total expenditure on the product decreases when the price rises, the price elasticity takes value greater than -∞ but less than -1

7 0
3 years ago
a 45 kg ice skater initially skating at a velocity of 3 m/s speeds up to a velocity of 5 m/s. calculate the difference in the ma
ad-work [718]

Answer: 90 kgm/s

Explanation:

The momentum (linear momentum) p is given by the following equation:

p=m.V

Where:

m=45 kg is the mass of the skater

V is the velocity

In this situation the skater has two values of momentum:

Initial momentum: p_{1}=m.V_{1}

Final momentum: p_{2}=m.V_{2}

Where:

V_{1}=3 m/s

V_{1}=5 m/s

So, if we want to calculate the difference in the magnitude of the skater's momentum, we have to write the following equation(assuming the mass of the skater remains constant):

p=p_{2}-p_{1}=m.V_{2}-m.V_{1}

p=m(V_{2}-V_{1})

p=45 kg(5 m/s - 3 m/s)

Finally:

p=90 kgm/s

4 0
3 years ago
Read 2 more answers
A motor keep a Ferris wheel (with moment of inertia 6.97 × 107 kg · m2 ) rotating at 8.5 rev/hr. When the motor is turned off, t
Talja [164]

Answer:

P = 133.13 Watt

Explanation:

Initial angular speed of the ferris wheel is given as

\omega_i = 2\pi f

\omega_i = 2\pi(8.5/3600)

\omega_i = 0.015 rad/s

final angular speed after friction is given as

\omega_f = 2\pi f

\omega_f = 2\pi(7.5/3600)

\omega_f = 0.013 rad/s

now angular acceleration is given as

\alpha = \frac{\omega_f - \omega_i}{\Delta t}

\alpha = \frac{0.015 - 0.013}{15}

\alpha = 1.27 \times 10^{-4} rad/s^2

now torque due to friction on the wheel is given as

\tau = I \alpha

\tau = (6.97 \times 10^7)(1.27 \times 10^{-4})

\tau = 8875.3 N m

Now the power required to rotate it with initial given speed is

P = \tau \omega

P = 8875.3 \times 0.015

P = 133.13 Watt

8 0
3 years ago
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