The specific heat capacity of the metal is
Explanation:
When a substance absorbs a certain amount of heat, its temperature increases according to the equation:
where
Q is the amount of heat absorbed
m is the mass of the substance
C is its specific heat capacity
is the increase in temperature of the substance
For the metal in this problem, we have:
m = 0.3 kg
Q = 9000 J
Therefore, its specific heat is:
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Answer:
the magnitude and direction of the uniform electric field is 1846.38 N/C and UPWARD respectively
Explanation:
Given the data in the question;
mass m = 1.30 g = 1.30 × 10⁻³ kg
Charge q = +6.90 µC = 6.90 × 10⁻⁶ C
we know that; g = 9.8 m/s
assuming gravity and the electrostatic force are the only forces exerted on the particle, hence the relation is;
F = mg and F = Eq
so
mg = Eq
make E subject of formula
E = mg / q
so we substitute
E = [ (1.30 × 10⁻³) × 9.8 ] / 6.90 × 10⁻⁶
E = 0.01274 / 6.90 × 10⁻⁶
E = 1846.38 N/C
Since the charge is positive ( + ), { direction is Upward }
Therefore, the magnitude and direction of the uniform electric field is 1846.38 N/C and UPWARD respectively
<h2>Answer</h2>
25 miles/hour
<h2>Explanation</h2>
Given that,
<em>A pilot can travel with wind = 416miles </em>
<em>A pilot can travel against wind = 336miles</em>
<em>A pilot can speed without wind = 235miles/hour </em>
<em />
<em />
let wind speed = v miles/hr
pilot's speed with the wind = 235<em>+ v</em>
pilot's speed against the wind = 235 - v
<h2>
Time = distance / speed</h2>
416 / (235 + v) = 336 / (235 - v)
416(235 - v) = 336(235+v)
97760 - 416v = 78960 + 336v
97760 - 78960 = 416v + 336v
18800 = 752v
v = 18800/752
v = 25 miles/hour
wind speed = 25 mph