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lisabon 2012 [21]
3 years ago
13

The left end of a rod of length and rotational inertia is attached to a frictionless horizontal surface by a frictionless pivot,

as shown above. Point C marks the center (midpoint) of the rod. The rod is initially motionless but is free to rotate around the pivot. A student will slide a disk of mass toward the rod with velocity 0 perpendicular to the rod, and the disk will stick to the rod a distance x from the pivot. The student wants the rod-disk system to end up with as much angular speed as possible

Physics
1 answer:
natima [27]3 years ago
6 0

Answer:

See explaination

Explanation:

please kindly see attachment for the step by step solution of the given problem.

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Answer:

Explanation:

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Equating cenrtipetal force and frictionl force in the case of car A

mv² / R = μmg

R = v² /μg

= 26.8 x 26.8 / .335 x 9.8

= 218.77 m

In case of moton of car B

mv² / R = μmg

v²  = μRg

= .683  x 218.77x 9.8

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Answer:

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Explanation:

This problem can be easily solved using the principle of linear momentum conservation. Which tells us that momentum is preserved before and after the collision.

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