The left end of a rod of length and rotational inertia is attached to a frictionless horizontal surface by a frictionless pivot,
as shown above. Point C marks the center (midpoint) of the rod. The rod is initially motionless but is free to rotate around the pivot. A student will slide a disk of mass toward the rod with velocity 0 perpendicular to the rod, and the disk will stick to the rod a distance x from the pivot. The student wants the rod-disk system to end up with as much angular speed as possible
1 answer:
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Answer:
Explanation:
The attached figure shows the whole description. Considering the applied force is 100 N.
The acceleration of both blocks A and B,
Firstly calculating the mass m using the second law of motion as :
F = ma
m is the mass
m = 125 kg
It suddenly encounters a surface that supplies 25.0 N a friction, F' = 25 N
So, the new acceleration of the block is . Hence, this is the required solution.
