An electric engine turning a workshop sanding rotation at 1.00 × 10² rev/min is switched off. Take the wheel includes a regular negative angular acceleration of volume 2.00 rad/s². 5.25 moments long it takes the grinding rotation to control.
<h3>What is negative angular acceleration?</h3>
- A particle that has a negative angular velocity rotates counterclockwise.
- Negative angular acceleration () is a "push" that is hence counterclockwise.
- The body will speed up or slow down depending on whether and have the same sign (and eventually go in reverse).
- For instance, when an object rotating counterclockwise slows down, acceleration would be negative.
- If a rotating body's angular speed is seen to grow in a clockwise direction and decrease in a counterclockwise direction, it is given a negative sign.
- It is known that a change in the linear acceleration correlates to a change in the linear velocity.
Let t be the time taken to stop.
ω = 0 rad/s
Use the first equation of motion for rotational motion
ω = ωo + α t
0 = 10.5 - 2 x t
t = 5.25 second
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Answer:
Time taken = 8.25 second
Explanation:
Given:
Force = 4000 N
Force = ma
4,000 = (1100)(a)
Acceleration = 3.6363 m/s²
v = u + at
0 = 30 + (3.6363)t
Time taken = 8.25 second
Answer: 11000 N
Explanation:
Given that,
Time required to stop car = 3.0 s
The car's momentum = 33,000
kg m/s
magnitude of force = ?
Recall that impulse is equal to the change in momentum of the car, hence
Impulse (I) = Momentum
(Since I = force x time, then
Force x time = momentum)
F x 3.0 s = 33,000 kg m/s
F = 33,000kg m/s / 3.0s
F = 11,000 N
Thus, 11000N of force was used to stop the car.
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Initial speed of the skateboarder (u) = 2 m/s
Distance covered (s) = 18 m
Time taken = 3.3 seconds
Let the acceleration be a.
Using seconds equation of motion:



a = 2.09 m/s^2
Now, Acceleration down the incline = g Sin Θ
g Sin Θ = a
9.8 × Sin Θ = 2.09
Sin Θ = 
Θ = 12.31°
Hence, the angle of the inclined plane is: Θ = 12.31°