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2 years ago

1. Dissolve 1 teaspoon of Epsom salts in a half cup of water.

Chemistry

2 answers:

Alex Ar [27]2 years ago

8 0

Answer:

1) $MgSO_4 + 2 NH_4OH \longrightarrow (NH_4)_2SO_4 + Mg(OH)_2$

2) Double displacement reaction

Explanation:

1) Balancing the equation:

The reaction: $MgSO_4 + NH_4OH \longrightarrow (NH_4)_2SO_4 + Mg(OH)_2$

In a first look we see that the amonium cations are unbalanced so:

$MgSO_4 + 2 NH_4OH \longrightarrow (NH_4)_2SO_4 + Mg(OH)_2$

Checking element by element we can see that the equation is balanced

2) In this reaction, the amonium discplaces the Mg to form the amonium sulfate. This is a displacement reaction.

Given that it also forms another product ( $Mg(OH)_2$ ) it's categorized as a double displacement reaction.

andreyandreev [35.5K]2 years ago

7 0

<span>1. The balanced equation for the reaction between magnesium sulfate and ammonia is MgSO4 + 2NH4OH → (NH4)2SO4 + Mg(OH)2
2. The reaction between magnesium sulfate and ammonia is double displacement.</span>

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Wet steam at 1100 kPa expands at constant enthalpy (as in a throttling process) to 101.33 kPa, where its temperature is 105°C. W

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Answer:

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Explanation:

Step 1.

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Step 2.

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Enthalpy of saturated vapour Hvap = 2779.7 J/g

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2 years ago

Read 2 more answers

A sample of gas at a pressure of 121.59 kPa, a volume of 31 L, and a temperature of 360 K contains how many moles of gas? A. 0.7

natali 33 [55]

Answer:

C. 1.3 mol

Explanation:

PV = nRT

where P is absolute pressure,

V is volume,

n is number of moles,

R is universal gas constant,

and T is absolute temperature.

Given:

P = 121.59 kPa

V = 31 L

T = 360 K

R = 8.3145 L kPa / mol / K

Find: n

n = PV / (RT)

n = (121.59 kPa × 31 L) / (8.3145 L kPa / mol / K × 360 K)

n = (3769.29 L kPa) / (2993.22 L kPa / mol)

n = 1.26 mol

Round to two significant figures, there are 1.3 moles of gas.

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