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4 years ago

What type of atom is hydrogen with an atomic mass of 1 and 2 electrons

Chemistry

1 answer:

Charra [1.4K]4 years ago

7 0

Answer:

This would be the hydride ion where H gains an electron from a metal such as Na

Explanation:

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What is the chemical formula of sodium azide?

Hunter-Best [27]

NaN₃ is the chemical formula for Sodium Azide

3 0

3 years ago

: Citric acid, H3C6H5O7, is a triprotic acid. Consider a buffer system comprising H2C6H5O7 - and HC6H5O7 2- ions. What is the ne

olchik [2.2K]

Answer:

The Net reaction is

$H_3C_6H_5O_7 + 0H^- ----> H_2C_6H_5O_7^- +H_2O \ \ \ \ \ \ \ Main \ Reaction$
$H_2C_6H_5O_7^ - + OH^- ----> H_C_6H_5O_7^{ 2-} + H_2O \ \ \ \ Add \ NaOH$
$HC_6H_5O_7 ^{2-} + OH^- ---> C_6H_5O_7^{3-} +H_2O \ \ \ \ \ Add \ NaOH$

Explanation:

From the Question we are told that the buffers are

$H_2C_6H_5O_7^ -$ and $HC_6H_5O_7 ^{ 2-}$

When NaOH is added the Net ionic reaction would be

$H_3C_6H_5O_7 + 0H^- ----> H_2C_6H_5O_7^- +H_2O \ \ \ \ \ \ \ Main \ Reaction$
$H_2C_6H_5O_7^ - + OH^- ----> H_C_6H_5O_7^{ 2-} + H_2O \ \ \ \ Add \ NaOH$
$HC_6H_5O_7 ^{2-} + OH^- ---> C_6H_5O_7^{3-} +H_2O \ \ \ \ \ Add \ NaOH$

8 0

3 years ago

Read 2 more answers

Some

Misha Larkins [42]

density is defined as mass per volume.. so 94 mL makes no sense.

7 0

3 years ago

The ""size"" of an atom is sometimes defined by the radius of a sphere that contains 90% of the charge density of the electrons.

vfiekz [6]

Answer:

3/2a

Explanation:

The complete step by step answer is found in the attachment

8 0

4 years ago

At a particular temperature, K 3.39 for the reaction SO2(9) + NO2(9) SOs(9) +NO(9) If all four gases had initial concentrations

Korvikt [17]

Answer:

The equilibrium concentrations are:

[SO2]=[NO2] = 0.563 M

[SO3]=[NO] = 1.04 M

Explanation:

Given:

Equilibrium constant K = 3.39

[SO2] = [NO2] = [SO3] = [NO] = 0.800 M

To determine:

The equilibrium concentrations of the above gases

Calculation:

Set-up an ICE table for the given reaction

$SO2(g) + NO2(g)\rightleftharpoons SO3(g) + NO(g)$

I 0.800 0.800 0.800 0.800

C -x -x +x +x

E (0.800-x) (0.800-x) (0.800+x) (0.800+x)

The equilibrium constant is given as:

$Keq = \frac{[SO3][NO]}{[SO2][NO2]}=\frac{(0.800+x)^{2}}{(0.800-x)^{2}}$

$3.39=\frac{(0.800+x)^{2}}{(0.800-x)^{2}}$

x = 0.2368 M

[SO2]=[NO2] = 0.800 -x = 0.800 - 0.2368 = 0.5632 M

[SO3]=[NO] = 0.800 +x = 0.800 + 0.2368 = 1.037 M

4 0

3 years ago