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Alchen [17]
3 years ago
7

What is the momentum of a 750-kg car traveling at a velocity of a 25 m/s?

Chemistry
1 answer:
hichkok12 [17]3 years ago
3 0

Momentum = mass x velocity 750x25 = 18750 kg-m/s.


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Completely reacting 150.0 g of a substance with oxygen releases 395.1 J of energy. How much energy would be released if 450.0 g
MrMuchimi
To solve this problem we just need to use the rule of three:
150g..................395.1J
450g................xJ

x = 450*395.1/150 = 1185,3J

450.0 g of the substance completely reacted with oxygen will produce 1.1853 kJ(<span>kiloJoule</span>)
4 0
3 years ago
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Determine the mechanical energy of this object: a 1-kg ball sits on a 10-meter high cliff.
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Mechanical energy = mass x acceleration due to gravity x height 
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8 0
2 years ago
Find the vapor pressure of a water solution in which the
zheka24 [161]

Answer:

The vapor pressure in solution is 0,0051 atm

Explanation:

This is the formula for vapor pressure lowering, the colligative property.

P vapor = Pressure sv pure . Xsv

Where Xsv is data.

Xsv means Molar fraction (moles solvent/total n° moles)

Vapor pressure of water, pure is 17.5 mmHg

P vapor = 0,0313 atm . 0163

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A solution will have less vapor pressure than that observed in the pure solvent.

5 0
3 years ago
The specific rotation of (S)-2-butanol is +13.5. If 0.119 g of its enantiomer is dissolved in 10.0 mL of ethanol and
larisa86 [58]

Answer:

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The formula for the observed rotation (α) of an optically active sample is

α = [α]<em>lc </em>

where

<em>l</em> = the cell path length in decimetres

<em>c</em> = the concentration in units of g/100 mL

[α] = the specific rotation in degrees  

1. Convert the concentration to units of g/100 mL

c = \frac{\text{0.119 g}}{\text{10.0 mL}} \times \frac{10 }{10 } =\frac{\text{1.19 g}}{\text{100 mL}}

2. Calculate the observed rotation

\alpha = (+13.3 ^{\circ}) \times 1.19 \times 1 = +15.8^{\circ}

7 0
3 years ago
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