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2 years ago

How does changing the amount of one substance affect a mixtures identity and a compounds identity iscience?

Chemistry

2 answers:

pychu [463]2 years ago

5 0

Explanation:

A compound is defined as follows.

Compounds are pure substance.
The atoms bonded in a compound are in specific proportion.
A compound is formed by chemical combination.
For a compound, melting point and boiling point is defined.

A mixture is defined as follows.

Mixtures are impure substance.
The bonded atoms in a mixture are in any proportion.
A mixture is formed by physical combination.
For a mixture, melting point and boiling point is not defined.

On changing the amount of one substance will affect the formation of compound as a compound requires atoms to be bonded in a specific proportion. Whereas changing the amount of one substance will not affect the formation of mixtures as atoms can be bonded in any proportion in a mixture.

KonstantinChe [14]2 years ago

3 0

According to the Law of Definite Proportions from Dalton's Atomic Theory, every compound has a fixed ratio of the mass or moles of its individual elements. This is obeyed by balancing the reactions through stoichiometric coefficients. When you increase the concentration of one substance by adding its amount, then, the other elements would also increase in order to maintain that fixed ratio.

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Calculate the total mass of the protons and electrons in 19 9F. Use 1.007825 amu as the mass of 11H (mass of a proton and an ele

SVETLANKA909090 [29]

Explanation:

Atomic mass means the sum of total number of protons and neutrons present in an atom.

When an atom is neutral then number of protons equal the number of electrons.

Mass of a proton equals to 1.007276 u, mass of neutron equals to 1.008664 u.

For example, in a $^{19}_{9}F$ atom there are total 9 protons and number of neutrons is 19 - 9 = 10.

Since, it is a neutral atom so number of electrons will also be 9.

So, total mass will be calculated as follows.

Total mass = 9 (mass of electron + mass of proton)

= 9 (1.007825 u)

= 9.07043 u

Therefore, we can conclude that total mass of protons and electrons in $^{19}_{9}F$ is 9.07043 u.

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2 years ago

(NEED HELP ASAP)

zheka24 [161]

1&3 are the answers lmk if it’s wrong

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2 years ago

A piece of brass is found to have a mass of 24.32 g. When placed in a graduated cyclinder with an initial reading of 5.60 mL the

Jobisdone [24]

Answer:

$\rho=3.1g/mL$

Explanation:

Hello,

In this case, considering that the density of a body is computed given its mass and volume:

$\rho =\frac{m}{V}$

Taking into account that the mass is 24.32 g and the volume is computed via the difference between the volume of the water with the brass and the volume of water by itself as follows:

$V=13.50mL-5.60mL=7.9mL$

The density of the piece of brass turns out:

$\rho =\frac{24.32g}{7.9mL}\\\\\rho=3.1g/mL$

Best regards.

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Which of the following fractions can be used in the conversion of 25 m3 to the unit cm3?

zaharov [31]

your answer would be C hope this helps

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puteri [66]

Answer:

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(True)

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