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Digiron [165]
3 years ago
7

How does changing the amount of one substance affect a mixtures identity and a compounds identity iscience?

Chemistry
2 answers:
pychu [463]3 years ago
5 0

Explanation:

A compound is defined as follows.

  • Compounds are pure substance.
  • The atoms bonded in a compound are in specific proportion.
  • A compound is formed by chemical combination.
  • For a compound, melting point and boiling point is defined.

A mixture is defined as follows.

  • Mixtures are impure substance.
  • The bonded atoms in a mixture are in any proportion.
  • A mixture is formed by physical combination.
  • For a mixture, melting point and boiling point is not defined.

On changing the amount of one substance will affect the formation of compound as a compound requires atoms to be bonded in a specific proportion. Whereas changing the amount of one substance will not affect the formation of mixtures  as atoms can be bonded in any proportion in a mixture.

KonstantinChe [14]3 years ago
3 0
According to the Law of Definite Proportions from Dalton's Atomic Theory, every compound has a fixed ratio of the mass or moles of its individual elements. This is obeyed by balancing the reactions through stoichiometric coefficients. When you increase the concentration of one substance by adding its amount, then, the other elements would also increase in order to maintain that fixed ratio.
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Answer: 1:4.69

Explanation:

The ratio can be expressed as:

Ua/Ub= √(Mb/Ma)

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Ua/Ub= √(44/2)

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When methanol, CH 3 OH , is burned in the presence of oxygen gas, O 2 , a large amount of heat energy is released. For this reas
luda_lava [24]

<u>Answer:</u> The mass of methanol that must be burned is 24.34 grams

<u>Explanation:</u>

We are given:

Amount of heat produced = 581 kJ

For the given chemical equation:

CH_3OH(g)+\frac{3}{2}O_2(g)\rightarrow CO_2(g)+2H_2O(l);\Delta H=-764kJ

By Stoichiometry of the reaction:

When 764 kJ of heat is produced, the amount of methanol reacted is 1 mole

So, when 581 kJ of heat will be produced, the amount of methanol reacted will be = \frac{1}{764}\times 581=0.7605mol

To calculate mass for given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of methanol = 0.7605 moles

Molar mass of methanol = 32 g/mol

Putting values in above equation, we get:

0.7605mol=\frac{\text{Mass of methanol}}{32g/mol}\\\\\text{Mass of methanol}=(0.7605mol\times 32g/mol)=24.34g

Hence, the mass of methanol that must be burned is 24.34 grams

4 0
3 years ago
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