<u>Answer</u>:
A precipitation is said to be complete precipitation when no further precipitate can be formed in the process.
<u>Explanation</u>:
Precipitation is the reaction of creating solid from the solution. In precipitation reactions, insoluble salts are formed when two solutions containing soluble salts are combined.
These two solutions contain different salts and have either cation or anion pairing. This reaction helps in the determination of ions in a solution. The solubility table is being used to predict the precipitation reaction. It occurs in solid when one solid’s concentration is above solubility.
For emission n=3 to n=1 The energy will be released
When an electron transitions from a lower state of energy energy level, absorption spectra are formed. When an electron transitions from a higher energy state to a lower energy state, emission spectra are produced.
To see a wavelength released, electrons would have to go down energy levels to view an emission spectra, limiting our solution options to And because n=3 to n=1 has more energy emitted than n=2 to n=1, the one with more energy emitted will have a shorter wavelength because wavelength and energy are inversely related. Energy will be released as an electron transitions from a higher energy state 3 to a low energy state 1.
To know more about emission spectra refer to brainly.com/question/14649237
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Answer:
0.134 moles of H₂ can be formed if a 3.25g sample of Mg reacts with excess HCl
Explanation:
The balanced reaction is:
Mg + 2 HCl → MgCl₂ + H₂
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles react:
- Mg: 1 mole
- HCl: 2 moles
- MgCl₂: 1 mole
- H₂: 1 mole
Being:
- Mg: 24. 31 g/mole
- H: 1 g/mole
- Cl: 35.45 g/mole
the molar mass of the compounds participating in the reaction is:
- Mg: 24.31 g/mole
- HCl: 1 g/mole + 35.45 g/mole= 36.45 g/mole
- MgCl₂: 24.31 g/mole + 2*35.45 g/mole= 95.21 g/mole
- H₂: 2*1 g/mole= 2 g/mole
Then, by stoichiometry of the reaction, the following quantities of mass participate in the reaction:
- Mg: 1 mole* 24.31 g/mole= 24.31 g
- HCl: 2 moles* 36.45 g/mole= 72.9 g
- MgCl₂: 1 mole* 95.21 g/mole= 95.21 g
- H₂: 1 mole* 2 g/mole= 2 g
Then you can apply the following rule of three: if by stoichiometry 24.31 grams of Mg form 1 mole of H₂, 3.25 grams of Mg how many moles of H₂ will they form?
moles of H₂= 0.134
<u><em>0.134 moles of H₂ can be formed if a 3.25g sample of Mg reacts with excess HCl</em></u>
Answer: Left Arrow Far right arrow and center left arrow
Explanation:
These three arrows are correct due to heat transfers to cooler temp environments which allows the expansion of speed for molecules in their environment.
