Answer:
18.22874999999973
I recommend you to round the nearest 1 d.p
Explanation:
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According to avogadro constant, the number of units in one mole of any substance contain 6.022 x10 ^23 atoms
therefore the number of o atoms in one mole of CuSO4 = 6.022 x 10 ^ 23
Answer:
18.066 × 10²³ particles
Explanation:
Given data:
Number of moles = 3 moles
Number of particles = ?
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
18 g of water = 1 mole = 6.022 × 10²³ molecules of water
1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen
For 3 moles of substance:
One mole = 6.022 × 10²³ particles
3 mol × 6.022 × 10²³ particles/ 1 mol = 18.066 × 10²³ particles
Answer:
Given, 0.29 g of hydrocarbon produces 448ml of CO2 at STP. then, C2H5 is the emperical formula of hydrocarbon . n = 2 , hence, molecular formula will be C4H10
The potassium will donate one of its valence electrons