Answer:
The correct answer is : 'the concatenation of NO will increase'.
Explanation:
Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.
This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.
If the temperature is increased, so according to the Le-Chatlier's principle , the equilibrium will shift in the direction where increase in temperature occurs.

As, this is an endothermic reaction, increasing temperature will add more heat to the system which move equilibrium in the forward reaction with decrease in temperature. Hence, the equilibrium will shift in the right direction.
So, the concatenation of NO will increase.
The enthalpy of this reaction is -296. 8 kJ/mol.
The equation of the reaction is;
S(s) + O2(g) -----> SO2(g)
Recall that the enthalpy of the reaction can be obtained from the formula;
ΔHrxn = ΔHf(products) - ΔHf(reactants)
We know that;
ΔHf S(s) = 0 KJ/mol
ΔHf O2(g) = 0 KJ/mol
ΔHf SO2(g) = -296. 8 kJ/mol
Hence;
ΔHrxn = -296. 8 kJ/mol - [0 KJ/mol + 0 KJ/mol]
ΔHrxn = -296. 8 kJ/mol
Learn more: brainly.com/question/13164491
Answer:
0.053 M is the concentration of X after 196 seconds.
Explanation:
Initial concentration of the X =
Time taken by the sample, t = 196 s
Final concentration of the X after t = [A] =?
Rate constant of the reaction = k = 
Formula used :
![[A]=[A_o]\times e^{-kt}](https://tex.z-dn.net/?f=%5BA%5D%3D%5BA_o%5D%5Ctimes%20e%5E%7B-kt%7D)
where,
Now put all the given values in this formula, we get
![[A]=[1.0M]\times e^{-1.50\times 10^{-2} s^{-1}\times 196 s}](https://tex.z-dn.net/?f=%5BA%5D%3D%5B1.0M%5D%5Ctimes%20e%5E%7B-1.50%5Ctimes%2010%5E%7B-2%7D%20s%5E%7B-1%7D%5Ctimes%20196%20s%7D)
![[A]=0.053 M](https://tex.z-dn.net/?f=%5BA%5D%3D0.053%20M)
0.053 M is the concentration of X after 196 seconds.
A=79, N=44 lmk if I’m wrong ?