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harkovskaia [24]
3 years ago
15

Hot air at 80°C is blown over a 2-m by> on0 4-m flat surface at 30°C. If the average? convection heat transfer coefficient va

ries between 20 W/m2 °C and 100 W/m °C, draw a relation between the rate of heat transfer from the air to the 80°C Air 30°C plate.(nm kW) and the convection heat transfer coefficient
Chemistry
1 answer:
mars1129 [50]3 years ago
7 0

Explanation:

The given data is as follows.

       T_{air} = 80 ^{o}C,       T_{surface} = 30 ^{o}C

Area of the flat plate is 2 × 4 = 8 m^{2}.

Average convection heat transfer coefficient (h_(avg)) = \frac{(20 + 100) W/m^{2} ^{o}C}{2} = 60 W/m^{2} ^{o}C}.

Hence, formula to calculate heat transfer through convection from air to the water is given as follows.

                    q = h_{avg} \times A_{surface} \times (T_{air} - T_{surface})

                        = 60 W/m^{2} ^{o}C} \times 8 m^{2} \times [(80 - 30)]^{o}C

                        = 24000 W

or,                     = 24 kW

Hence, the direction of heat flow is from air to the surface.

Thus, we can conclude that transfer of heat is 24 kW.

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Answer:

The correct answer is : 'the concatenation of NO will increase'.

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

If the temperature is increased, so according to the Le-Chatlier's principle , the equilibrium will shift in the direction where increase in temperature occurs.

2NOBr(g)\rightleftharpoons 2NO(g) + Br_2(g)

As, this is an endothermic reaction, increasing temperature will add more heat to the system which move equilibrium in the forward reaction with decrease in temperature. Hence, the equilibrium will shift in the right direction.

So, the concatenation of NO will increase.

7 0
3 years ago
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Answer:

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6 0
3 years ago
Sulfur reacts with oxygen to form sulfur dioxide (SO2(g), Delta. Hf = â€"296. 8 kJ/mol) according to the equation below. Upper S
Rus_ich [418]

The enthalpy of this reaction is -296. 8 kJ/mol.

The equation of the reaction is;

S(s) + O2(g) -----> SO2(g)

Recall that the enthalpy of the reaction can be obtained from the formula;

ΔHrxn = ΔHf(products) - ΔHf(reactants)

We know that;

ΔHf S(s) = 0 KJ/mol

ΔHf O2(g) =  0 KJ/mol

ΔHf SO2(g) = -296. 8 kJ/mol

Hence;

ΔHrxn =  -296. 8 kJ/mol - [0 KJ/mol + 0 KJ/mol]

ΔHrxn = -296. 8 kJ/mol

Learn more: brainly.com/question/13164491

7 0
2 years ago
A chemical reaction that is first-order in X is observed to have a rate constant of 1.50 × 10–2 s–1. If the initial concentratio
elena-s [515]

Answer:

0.053 M is the concentration of X after 196 seconds.

Explanation:

Initial concentration of the X = [A_o]=1.0 M

Time taken by the sample, t = 196 s

Final concentration of the X after t = [A] =?

Rate constant of the reaction = k = 1.50\times 10^{-2} s^{-1}

Formula used :

[A]=[A_o]\times e^{-kt}

where,

Now put all the given values in this formula, we get

[A]=[1.0M]\times e^{-1.50\times 10^{-2} s^{-1}\times 196 s}

[A]=0.053 M

0.053 M is the concentration of X after 196 seconds.

3 0
3 years ago
Use the periodic table to determine which of the
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