Answer:
rats. that's all i know of Just about everything except the mother hen if they are natural hatch. Even when you incubate them there are threats. The healthy chicks will mob the weak ones, the older chicks (even by a day) will pick on the younger ones. Temperature extremes will threaten them as they need warm, humid conditions with gradual drops in surrounding temps in the brooder box. Early disease is sometimes a problem and all chicks should be started on medicated chick feed for the first few weeks to prevent several digestive diseases. Even the water dispenser can be a threat as newly hatched chicks will immerse themselves in an open water container so care should be taken to supply water in a self feeding covered dish.
Explanation:
Answer:
As per Dalton's law of Partial pressure,
The total pressure of a mixture of gases is equal to sum of partial pressure of individual components of the mixture.
So, P=P_H+P_N+P_WP=P
H
+P
N
+P
W
\implies 864\ mm=220\ mm+410\ mm+P_W\implies⟹864 mm=220 mm+410 mm+P
W
⟹ P_W=864-630=234P
W
=864−630=234 mm of Hg.
Explanation:
Hope it helps<3
132.13952<span> grams - I believe</span>
Dhangaman the smiths lama
Answer:
Rate = 43 M⁻¹s⁻¹[NO₂][O₃]
Explanation:
We need to find the reaction order in
rate = (NO₂ )ᵃ (O₃ )ᵇ
given:
( NO₂ ) M ( O₃ ) M Rate M/s
0.10 0.33 1.420 (1)
0.10 0.66 2.840 (2)
0.25 0.66 7.10 (3)
When keeping the NO₂ concentration constant in the first two while doubling the concentration of O₃ , the rate doubles. Therefore it is first order with respect to O₃
Comparing (2) and (3) increasing the concentration of NO₂ by a factor of 2.5 and keeping O₃ constant , increased the rate by a factor of 2.5. Therefore the rate is first order with respect to NO₂
Then rate law is
= k (NO₂) (O₃ )
To find k take any of the three and substitute the values to find k:
1.420 M/s = k (0.10)M x (0.33)M ⇒ k = 43 /Ms
Then the answer is Rate = 43 M⁻¹s⁻¹[NO₂][O₃]