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kogti [31]
3 years ago
15

20 points! Help ASP! Your answer must be explained!

Chemistry
2 answers:
Mariana [72]3 years ago
5 0
<span>b.mixtures are made up of more than one component</span>
aalyn [17]3 years ago
3 0

A mixture cannot be separated by physical means

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Write the chemical equations involved in this experiment and how that the rate of disappearance of [S2O8^2-] is proportional to
Ne4ueva [31]

S₂O₈²⁻

(aq) + 2I⁻

(aq) → I₂(aq) + 2SO₄

²⁻(aq)

2S₂O₃²⁻

(aq) + I₂(aq) → S₄O₆²⁻

(aq) + 2I⁻

(aq)

<u>Explanation:</u>

S₂O₈²⁻

(aq) + 2I⁻

(aq) → I₂(aq) + 2SO₄

²⁻(aq)

To measure the rate of this reaction we must measure the rate of concentration change of one of  the reactants or products. To do this, we will include (to the reacting S₂O₈

²⁻  and I⁻

i) a small amount of sodium thiosulfate, Na₂S₂O₃,

ii) some starch indicator.

The added Na₂S₂O₃ does not interfere with the rate of above reaction, but it does consume the I₂  as soon as it is formed.

2S₂O₃²⁻

(aq) + I₂(aq) → S₄O₆²⁻

(aq) + 2I⁻

(aq)

This reaction is much faster than the previous, so the conversion of I2 back to I⁻  is  essentially instantaneous.

rate = \frac{dI2}{dt} = \frac{1/2 [S2O3^2^-]}{t}

5 0
3 years ago
What are the contents of a electron cloud?
PilotLPTM [1.2K]
Weast to east , east to west, nort to south, south to nort.
7 0
3 years ago
The combination of sucrose, sucrase, and water produces sucrase, glucose, and fructose. Which component of the reaction is the s
Pavlova-9 [17]

Answer:

Sucrose to is the substrate of the reaction because is a simple sugar( disaccharide) which produce glucose and fructose in the presence of sucrase or when it is hydrolysed.

6 0
1 year ago
The density of pure diamond is 3.5 g/cm°. What is the volume of a diamond with a mass of 0.25 g?
ValentinkaMS [17]

Answer:

0.071 is the correct answer using the formula d=m/v

3 0
2 years ago
Read 2 more answers
If 200.4g of water is mixed with 101.42g of salt the mass of the final solution would be reported as
d1i1m1o1n [39]

Answer:

301.8 g

Explanation:

We prepare a solution with 200.4 g of water (solvent) and 101.42 g of salt (solute). The mass of the solution is equal to the sum of the mass of the solvent and the mass of the solute.

m(solution) = m(solute) + m(solvent)

m(solution) = 200.4 g + 101.42 g

m(solution) = 301.8 g (we round-off to one decimal according to the significant figures rules)

8 0
2 years ago
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