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3 years ago

Who Discovered the neutral subatomic particles called neutrons

Chemistry

2 answers:

irina1246 [14]3 years ago

5 0

James CHadwick discovered the subatomic particles caled neutrons

ale4655 [162]3 years ago

3 0

Answer:

chadwick

Explanation:

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Howtocalculatethevolumeofcarbondioxideproducedwhen400gofmarblewereats.t.p<br>

lys-0071 [83]

Answer:

so 0.15 moles X 22.4 dm3/mole=3.36 dm3. Next we find the moles of hexane combusted, and then the moles of CO2. Finally, we find the volume of CO2 using the fact that at STP, 1 mole of gas = 22.4 dm3.

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3 years ago

What is the molar mass of zinc metal

hodyreva [135]

I believe it is 65.37.

Let me know if this is correct. Also good luck!!

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10. Which is an example of mechanical energy?*

gtnhenbr [62]

Answer: A golfer hitting a golf ball.

Explanation:

The atomic particles move more in this option than the others.

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3 years ago

A 0.75M solution of CH3OH is prepared in 0.500 kg of water. How many moles of CH3OH are needed?

4vir4ik [10]

Answer:

We need 0.375 mol of CH3OH to prepare the solution

Explanation:

For the problem they give us the following data:

Solution concentration 0,75 M

Mass of Solvent is 0,5Kg

knowing that the density of water is 1g / mL, we find the volume of water:

$d = \frac{g}{mL} \\\\ V= \frac{g}{d} = \frac{500g}{1 \frac{g}{mL} } = 500mL = 0,5 L$

Now, find moles of $CH_{3} OH$ are needed using the molarity equation:

$M = \frac{ moles }{ V (L)} \\\\\\molesCH_{3}OH = M . V(L) = 0,75 M . 0,5 L\\\\molesCH_{3}OH = 0,375 mol$

therefore the solution is prepared using 0.5 L of H2O and 0.375 moles of CH3OH, resulting in a concentration of 0,75M

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3 years ago

What will be the boiling point of a solution of 8 moles of sodium dichromate (Na2Cr2O7) dissolved in 8 kg of water? Use the foll

nexus9112 [7]

Answer:

1. 374.69 K

Explanation:

Hello,

In this case, pure water's boiling point is 373.15 K, thus by considering the boiling point increase equation:

$\Delta T=imKf$

Whereas i=2 since two ionic species are formed,actually, the experimental value is 2.42 so better work with it, thus:

$\Delta T=2.42*(\frac{8}{8}m)*0.512 Km^{-1}=1.239K$

Thus, the required boiling point is:

$T_b=373.15K+1.239K\\T_b=374.69K$

Regards.

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3 years ago

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