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ludmilkaskok [199]
3 years ago
11

A current is flowing clockwise around a loop placed flat on your desk. what would be the direction of the resulting magnetic fie

ld inside the loop? 1. downward 2. clockwise 3. coun
Physics
1 answer:
monitta3 years ago
4 0
We should use the right-hand rule in order to understand the direction of the magnetic field and to solve the problem.

Let's put the thumb of the right hand as the direction of the current in the loop, and then let's "wrap" the other fingers around it: the direction of the other fingers gives the direction of the magnetic field. Since the direction of the current (of the thumb) is clockwise, we see that inside the loop the other fingers are directed downward, so the magnetic field direction is downward.
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Brainliest if right.
jeka57 [31]

Answer:

the third law (for every action there is an equal and opposite reaction).

Explanation:

The skateboarder pushes backwards on the road (that is he applies a force on the road in a direction opposite the direction of intended motion). By Newton's third law, this action of the skateboarder causes an equal reaction of the road on the skateboarder in the opposite direction. Newton's third law states that action and reaction are equal but opposite in direction. So, the road in response to this backward force pushes the skateboarder in the forward direction causing the skateboarder and the skateboard to move in the forward direction.

5 0
3 years ago
A proton travels with a speed of 1.8×106 m/s at an angle 53◦ with a magnetic field of 0.49 T pointed in the +y direction. The ma
Likurg_2 [28]

Answer:

Magnetic force, F=1.12\times 10^{-13}\ N

Explanation:

It is given that,

Velocity of proton, v=1.8\times 10^6\ m/s

Angle between velocity and the magnetic field, θ = 53°

Magnetic field, B = 0.49 T

The mass of proton, m=1.672\times 10^{-27}\ kg

The charge on proton, q=1.6\times 10^{-19}\ C

The magnitude of magnetic force is given by :

F=qvB\ sin\theta

F=1.6\times 10^{-19}\ C\times 1.8\times 10^6\ m/s\times 0.49\ Tsin(53)

F=1.12\times 10^{-13}\ N

So, the magnitude of the magnetic force on the proton is 1.12\times 10^{-13}\ N. Hence, this is the required solution.

3 0
3 years ago
When large amplitude sound vibrates the ear significantly, a _______ results.
sladkih [1.3K]

The answer is B. High Pitch Sound

4 0
4 years ago
Question 1
kakasveta [241]

Answer:

W = 600 J

Explanation:

We have,

According to attached figure,

Height of the inclined plane is 60 m

Force acting on the block is 10 N

It is required to find the work must be done against gravity to move it to the top of the incline. The work done is given by :

W = mgh

or

W=F\times h\\\\W=10\times 60\\\\W=600\ J

So, the work done against the gravity is 600 J.

3 0
3 years ago
An object with a mass of m = 3.85 kg is suspended at rest between the ceiling and the floor by two thin vertical ropes.
Aleksandr-060686 [28]

The tension in the upper rope is determined as 50.53 N.

<h3>Tension in the upper rope</h3>

The tension in the upper rope is calculated as follows;

T(u) = T(d)+ mg

where;

  • T(u) is tension in upper rope
  • T(d) is tension in lower rope

T(u) = 12.8 N + 3.85(9.8)

T(u) = 50.53 N

Thus, the tension in the upper rope is determined as 50.53 N.

Learn more about tension here: brainly.com/question/918617

#SPJ1

6 0
2 years ago
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