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Sedbober [7]
3 years ago
9

An archer shot a 0.07 kg arrow at a target. The arrow accelerated at 4,000 m/s2 to reach a speed of 50.0 m/s as it left the bow.

During this acceleration, what was the net force on the arrow?
A) 280 N
B) .0000175 N
C) 57,142 N
D) 3.5 N
Physics
2 answers:
denpristay [2]3 years ago
3 0

Answer:

A. 280

Explanation:

saw5 [17]3 years ago
3 0
The answer is A ) 280 N
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A transverse wave on a string is described by the wave functiony(x, t) = 0.350 sin (1.25x + 99.6t)where x and y are in meters an
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The time interval that is between the first two instants when the element has a position of 0.175 is 0.0683.

<h3>How to solve for the time interval</h3>

We have y = 0.175

y(x, t) = 0.350 sin (1.25x + 99.6t) = 0.175

sin (1.25x + 99.6t) = 0.175

sin (1.25x + 99.6t) = 0.5

99.62 = pi/6

t1 = 5.257 x 10⁻³

99.6t = pi/6 + 2pi

= 0.0683

The time interval that is between the first two instants when the element has a position of 0.175 is 0.0683.

b. we have k = 1.25, w = 99.6t

v = w/k

99.6/1.25 = 79.68

s = vt

= 79.68 * 0.0683

= 5.02

Read more on waves here

brainly.com/question/25699025

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complete question

A transverse wave on a string is described by the wave function y(x, t) = 0.350 sin (1.25x + 99.6t) where x and y are in meters and t is in seconds. Consider the element of the string at x=0. (a) What is the time interval between the first two instants when this element has a position of y= 0.175 m? (b) What distance does the wave travel during the time interval found in part (a)?

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