Answer:
width of the slit = a = 0.0935 mm
Explanation:
width of central maximum for single slit diffraction is:
----- (1)
Distance between source and screen = L = 5.5 m
Width of bright band = w = 8 cm
= 0.08 m
λ = 680 nm
Width of the slit = a = ?
Arranging (1) for a
a = 0.0935 mm
You didn't give us anything other than the question. No options are provided so I cannot answer. Nobody can.
The awnser is C. Breast stroke Hope this helps :)