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3 years ago

A compound has the formula X2O3 where x is an unknown element. If the compound is 24.26% oxygen, what element does x represent?

Chemistry

1 answer:

Vinil7 [7]3 years ago

5 0

<h3>Answer:</h3>

Element X is Arsenic (Ar)

<h3>Explanation:</h3>

We are given the compound X₂O₃

The compound is 24.26% Oxygen

We are required to identify element X

<h3>Step 1: Determine the mass of Oxygen in the compound </h3>

Atomic mass of Oxygen is 16.0 g

There are three oxygen atoms in the compound

Therefore;

Mass of oxygen in the compound = 3 × 16

= 48 g

<h3>Step 2: Total mass of the compound </h3>

Total percentage = 100%

But, Oxygen in the compound is 24.26 % and has a mass of 48 g

Therefore;

Mass of the compound = (48 g ÷ 24.26 ) × 100

= 197.857 g

<h3>Step 3 mass of X in the compound </h3>

Since we know the mass of oxygen in the compound and the mass of the compound we can determine the mass of X

Mass of X in the compound = Mass of the compound - Mass of Oxygen in the compound

= 197.857 g - 48 g

= 149.857 g

But there are two atoms of X in the compound.

Therefore, molar mass of X = 149.857 g ÷ 2

= 74.929 g

<h3>Step 4: Identity of element X</h3>

We then we need to identify the element with a molar mass of 74.929 g

Therefore, the element represented above is Arsenic which has an atomic mass of 74.92.

Thus, our compound is Ar₂O₃

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When two atoms are bonded and have a large difference in electronegativity:<br> HELP PLEASEEE

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Answer:

Second option - The bond is very polar

Explanation:

Electronegativity of an basically refers to the degree at which an electron is able to attract electrons to itself.

There are different types of bonds between atoms, depending on the electronegativity of the atoms.

When there is a large difference in electronegativity, it pretty much means that one atom would draw electrons more than the other. When this happens, the bond is said to be polar because there is uneven distribution of the charges.

The second option is the correct answer in thus question.

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2 years ago

Show the relationship of number of moles and volume in Avogadro's law using data. Write your calculations and answer on a separa

leonid [27]

Answer:

See below ~

Explanation:

The calculated values of V/n :

⇒ 1.5/0.3 = 5

⇒ 3/0.6 = 5

⇒ 4.5/0.9 = 5

⇒ 6/1.2 = 5

⇒ 7.5/1.5 = 5

1. From this we understand that the calculated values of V/n remain constant, equal to <u>5</u> in this case.

2. The volume-mole graph will be a straight line passing through the origin. (Attached below)

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2 years ago

A liquid of density 1290 kg/m 3 flows steadily through a pipe of varying diameter and height. At Location 1 along the pipe, the

Gelneren [198K]

Answer:

114 kPa

Explanation:

By Bernoulli's equation when a fluid flows steadily through a pipe:

P + ρ*g*y + v² = constant in the pipe, where P is the pressure, ρ is the density of the fluid, g is the gravity acceleration (9.8 m/s²), y is the high, and v the velocity.

By the continuity equation, the liquid flow must be constant in the pipe, and then:

A1*v1 = A2*v2

Where A is the area, v is the velocity, 1 is the point 1, and 2 the point 2 in the pipe. The are is the circle area: π*(d/2)². So:

π*(0.105/2)²*9.91 = π*(0.167/2)²*v2

0.007v2 = 0.027

v2 = 3.9 m/s

Then:

P1 + ρ*g*y1 + v1² = P2 + ρ*g*y2 + v2²

ρ*g*y1 - ρ*g*y2 + v1² - v2² = P2 - P1

ρ*g*Δy + v1² - v2² = ΔP

ΔP = 1290*9.8*9.01 + 9.91² - 3.9²

ΔP = 113,987.42 Pa

ΔP = 114 kPa

8 0

2 years ago

"1s22s22p63s2" is the electron configuration for which element

vazorg [7]

MAGNESIUM(Mg) posses the up mentioned electronic configuration

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3 years ago

The reaction of 4.8g of sulfur and 5.4g aluminum yields 4.5g Al2S3. 3S+2AL-->Al2S3 Determine the percent yield of Al2S3.

Goshia [24]

Answer:

59.9% is the percent yield for the 4.5 g of produced Al₂S₃

Explanation:

Let's determine the reaction:

3S + 2Al → Al₂S₃

First of all, let's determine the limiting reactant. We need to convert the mass to moles:

4.8 g /32.06g/mol = 0.150 moles of S

5.4 g / 26.98 g/mol = 0.200 moles of Al

3 moles of S react to 2 moles of Al

Then, 0.150 moles of S may react to (0.150 . 2)/3 = 0.1 ,moles of Al

We have 0.200 moles and we only have 0.1. As we have excess of Al, this is the excess reactant. In conclussion, the limiting reagent is S.

2 moles of Al react to 3 moles of S

Then 0.2 moles of Al may react to (0.2 . 3) /2 = 0.3 moles of S. (We only have 0.150 moles)

Let's go to the product, 3 moles of S can produce 1 mol of Al₂S₃

Then 0.150 moles of S, may produce (0.150 . 1) /3 = 0.05 moles.

We convert moles to mass to determine the thoretical yield:

0.05 mol . 150.15g /mol = 7.50g

Percent yield = (Produced yield/Theoretical yield) . 100

% = (4.5g / 7.5g) . 100 = 59.9%

8 0

2 years ago