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Scorpion4ik [409]
3 years ago
14

. An ideal vapor compression refrigeration cycle operates with a condenser pressure of 900 kPa. The temperature at the inlet to

the compressor is -5oC. If this device operates using R134a as the working fluid, calculate the actual COP of this device as well as the maximum theoretical COP.
Engineering
1 answer:
tatuchka [14]3 years ago
8 0

Answer:

Actual COP = 5.368

Maximum theoretical COP = 6.368

Explanation:

Given - An ideal vapor compression refrigeration cycle operates with a condenser pressure of 900 kPa. The temperature at the inlet to the compressor is -5oC.

To find -  If this device operates using R134a as the working fluid. Calculate the actual COP of this device as well as the maximum theoretical COP.

Proof -

Given that,

An ideal vapor compression refrigeration cycle operates with a condenser pressure of 900 kPa.

From Refrigerant 134-a Table

At T1 = -5°C

h1 = 247.505 KJ/kg

S1 = 0.93434 KJ/kg

At P2 = 900 KPa

S1 = S2

h2 = 274.679 Kj/Kg

h3 = h4 = 101.61 KJ/g

So,

Compressor work (Wc) = h2 - h1

                                       = 274.679 - 247.505

                                       = 27.174

⇒Compressor work (Wc) = 27.174 KJ/kg

Now,

Heat out (Qout) = h2 - h3

                          = 274.679 - 101.61

                          = 173.069

⇒Heat out (Qout) = 173.069 KJ/kg

Now,

Heat input (Qin) = h1 - h4

                          = 274.505 - 101.61

                          = 145.895

⇒Heat input (Qin) = 145.895 KJ/kg

So,

Actual COP at the refrigerator is -

(COP)R = (Qin)/(Wc)

            = (145.895)/ (27.174)

            = 5.368

⇒Actual COP = 5.368

Now,

Maximum theoretical COP is -

(COP) = (Qout)/(Wc)

          = (173.069)/ (27.174)

          = 6.368

⇒Maximum theoretical COP = 6.368

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Answer:

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Explanation:

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a = (29 m/s – 11.2 m/s) / 321 m = 2.2 m/s2

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Answer:

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The tolerance of a quantity is the maximum limit of variation allowed for that quantity.

To find it we must have the value of the magnitude, its closest value is the average value, this value can be given or if it is not known it is calculated with the formula

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fluctuation for x₁

        Δx₁ = 2.17000 / 2.2142857145

        Tolerance = 100 - 97.999999991

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          Δx₂ = 1.0200445

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c)

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       tolerance = 100 -101.962896

       tolerance = 1.96%

d)

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       Δx₁ = 2.20144927 / 2.24637681 = 0.98000043

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e)

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