A common carnival ride, called a gravitron, is a large r = 11 m cylinder in which people stand against the outer wall. the cylin
1 answer:
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Answer:
Magnitude of magnetic field is 1.29 x 10⁻⁴ T
Explanation:
Given :
Current flowing through the wire, I = 16.9 A
Length of wire. L = 0.69 m
Magnetic force experienced by the wire, F = 1.5 x 10⁻³ N
Consider B be the applied magnetic field.
The relation to determine the magnetic force experienced by current carrying wire is:
F = ILBsinθ
Here θ is the angle between magnetic field and current carrying wire.
According to the problem, the magnetic field and current carrying wire are perpendicular to each other, that means θ = 90⁰. So, the above equation becomes:
F = ILB
Substitute the suitable values in the above equation.
B = 1.29 x 10⁻⁴ T
Answer:
Zero
Explanation:
Given the equation of an ellipse:
The eccentrity of an ellipse is given by:
For a circle, we have
Therefore the eccentricity of a circle is
Answer:
75 N
Explanation:
In this problem, the position of the crate at time t is given by
The velocity of the crate vs time is given by the derivative of the position, so it is:
Similarly, the acceleration of the crate vs time is given by the derivative of the velocity, so it is:
[m/s^2]
According to Newton's second law of motion, the force acting on the crate is equal to the product between mass and acceleration, so:
where
m = 5.00 kg is the mass of the crate
At t = 4.10 s, the acceleration of the crate is
And therefore, the force on the crate is: