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Jet001 [13]
2 years ago
10

Which statement is true? A) Cells come in different shapes, but are all about the same size—very, very small. B) Cells come in di

fferent shapes and different sizes. C) Cells all have the same shape, but come in different sizes. D) Cells are all the same shape and size—small and rounded.
Physics
1 answer:
Darya [45]2 years ago
3 0

Answer: B) Cells come in different shapes and different sizes.

Explanation:

Cell is the basic unit of life. Each cell forms the an integral component of the body of the living organism. The cell structure and function varies from organism to organism. The cells of the plants are comparatively larger than the animal cells. The plant cells are usually rectangular in shape whereas that of animals are usually circular or round in shape. The shape and size of the cells can vary depending upon the function and structure of the organism.

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What are the answers please help
aleksandr82 [10.1K]

Answer:

a.) The main scale reading is 10.2cm

b.) Division 7 = 0.07

c.) 10.27 cm

d.)  10.31 cm

e.)  10.24 cm  

Explanation:

The figure depicts a vernier caliper readings

a.) The main scale reading is 10.2 cm

The reading before the vernier scale

b.) Division 7 = 0.07

the point where the main scale and vernier scale meet

c.) The observed readings is

10.2 + 0.07 = 10.27 cm

d.) If the instrument has a positive zero error of 4 division

correct reading = 10.27 + 0.04 = 10.31cm

e.)  If the instrument has a negative zero error of 3 division

correct reading = 10.27 - 0.03 = 10.24cm  

3 0
3 years ago
1) A pendulum is configured to have a period of 2 seconds.
vazorg [7]

"The" (and any subsequent words) was ignored because we limit queries to 32 words.

3 0
3 years ago
You have been hired by a "storm chaser" as an assistant. This individual loves to find locations at which tornadoes and violent
Studentka2010 [4]

Answer:

58.44 C

Explanation:

Electric field is found by

E=\frac {\sigma}{\epsilon_o}=\frac {Q}{A\epsilon_o}

Therefore, the charge is

Q=EA\epsilon_o


Q= 4.00 ✕ 10^{6} N/C*1.65 *10^{6} m^{2}*8.854*10^{-12}= 58.4364 C


Therefore, required charge is 58.44 C

5 0
3 years ago
A ring is attached at the center of the underside of a trampoline. A sneaky teenager crawls under the trampoline and uses the ri
Karo-lina-s [1.5K]

Answer:

Explanation:

Given

Mass of mother m=79\ kg

Mother is released with a speed of v=2.5\ m/s

Assuming we need to find elastic Potential energy stored in Trampoline

Kinetic energy acquired  by Mother comes from Elastic Potential Energy stored in the spring

I.e. Elastic Potential Energy=Kinetic Energy of mother

\frac{1}{2}kx^2=\frac{1}{2}mv^2

E=\frac{1}{2}\times 79\times 2.5^2=246.875\ J

So 246.875 J of Energy is stored in the trampoline as he pull the ring

5 0
3 years ago
A system of inertia 0.47 kg consists of a spring gun attached to a cart and a projectile. The system is at rest on a horizontal
Vlad [161]

Answer:

v'=0.83m/a and v=10.2m/s

Explanation:

The information that we have is:

m_1=0.050kg\\m_2=0.47kg\\\theta = 40\\h=2.2m

The maximum height of the projectile is given by the equation

h=\frac{v^2sin^2\theta}{2g}

So, rearrange for the velocity,

v=\sqrt{\frac{2gh}{sin^2\theta}}\\v=\sqrt{\frac{2*9.8*2.2}{sin^2(40)}}\\v=10.2m/s

Apply the conservation of momentum,

mvcos(\theta)=m'v'

Then rearrange the recoil speed,

v'=\frac{mvcos\theta}{m_2}\\v'=\frac{0.05*10.2*cos40}{0.47}\\v'=0.83m/s\\

4 0
3 years ago
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