Answer:
The centripetal acceleration of the rock is decreases by a factor of 3.
Explanation:
Given that,
Radius of circle
Time period = T
Radius of new circle
We need to calculate the velocity
Using formula of velocity
The time period for new circle
The time period remains same.
Put the value in the equation
The acceleration of the rock is
We need to calculate the acceleration of the new rock
Using formula of acceleration
Put the value into the formula
Hence, The centripetal acceleration of the rock is decreases by a factor of 3.
Answer:
2.6 N
Explanation:
Given:
v₀ = 0 m/s
v = 22 m/s
t = 22 s
Find: a
v = at + v₀
(22 m/s) = a (22 s) + (0 m/s)
a = 1 m/s²
Newton's second law:
F = ma
F = (2.6 kg) (1 m/s²)
F = 2.6 N
As we know that electrostatic force is a conservative force
so we can say by the condition of conservative force
here we can rearrange the above equation as
now integrate both sides
Now we know by the definition of work done by a force is given by
now work done by conservative force is given as
Now from above work done by electric field to move charge from one point to other is given as
so here work done is given as
so change in potential energy is given by work done
The rate of change of velocity
Answer:
ΔEP = -1.36 J
Explanation:
Given:
- The complete question is as follows:
" A mass of 0.105 kg hangs from a vertical spring in the lab room. You pull down on the mass and throw it vertically downward. The speed of the mass just after leaving your hand is 5.20 m/s.
"
Find:
When the mass has moved downward a distance of 0.04 m, the speed of the mass has decreased to 1.39 m/s.
Solution:
- The initial velocity of the system vi = 5.20 m/s
- The mass m = 0.105 kg
- The final velocity of mass vf = 1.39 m/s
- Change in distance d = 0.04m
Solution:
- When the mass (m) is moved down by (d) the work-done by gravity P.E translates to change in kinetic energy K.E and elastic potential energy of the spring EP . The energy balance can be set as:
ΔEP + P.E = ΔK.E
ΔEP + m*g*h = 0.5*m*(vf^2-vi^2)
ΔEP = 0.5*m*(vf^2-vi^2) - m*g*h
ΔEP = 0.105* (- 9.81*0.04 + 0.5*(1.39^2-5.2^2) )
ΔEP = - 1.36 J
- Since, The work done by spring is negative because the displacement is downwards and the force is upwards.