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IceJOKER [234]
3 years ago
8

If a sample of NH3 gas at 689,1 mmHg has a volume of 607 2 mL and the presure is

Chemistry
1 answer:
never [62]3 years ago
8 0

Answer:

The answer to your question is V2 = 746.1 ml

Explanation:

Data

Pressure 1 = P1 = 689.1 mmHg

Volume 1 = V1 = 607.2 ml

Pressure 2 = P2 = 560.8 mmHg

Volume 2 = V2 = ?

Process

To solve this problem use Boyle's law

              P1V1 = P2V2

-Solve for V2

              V2 = P1V1/P2

-Substitution

               V2 = (689.1 x 607.2) / 560.8

-Simplification

                V2 = 746.1 ml

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Answer:

132g/mole

Explanation:

using the formula PV=nRT should be used to solve for the number of moles (n).  R is a constant which is 62.3637 L mmHG/mole K.

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