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3 years ago

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jason hits a baseball off a tee toward right field. the ball has a horizontal velocity of 10 m/s and lands 5 meters from the tee

. what is the height of the tee? show your work, including formula(s) and units.

1 answer:

Leni [432]3 years ago

8 0

Answer:

The height is 1,225 meters

Explanation:

DistanceX= speedX × time ⇒ time= (5 meters) ÷ (10 meters/second) = 0,5 seconds

DistanceY= high= (1/2) × g × (time^2) = (1/2) × 9,8 (meters/(second^2)) × 0,25 (second^2) = 1,225 meters

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A) $x=\pm \frac{A}{2\sqrt{2}}$

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Substituting $U=\frac{1}{2}kx^2$ into the last equation, we find the value of x:

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In this case, the kinetic energy is 1/10 of the total energy:

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3 years ago

If the pitched ball was traveling 77 mph before stanton's bat hit it and 120 mph after his bat hit it, by what amount did the sp

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here we will use the concept of Newton's III law

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$\Delta v = 6.72 mph$

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Answer:

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