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Sergeeva-Olga [200]
3 years ago
12

2.714 mole of helium has a mass of ______ grams. (Enter just the number for this one.)

Chemistry
1 answer:
kifflom [539]3 years ago
6 0

Hello!

To find the mass of helium, we need to multiply the total moles by the mass of helium. We are given 2.714 moles of helium, and the mass of helium is about 4.00 grams. Now, we multiply the two values together to get the grams.

2.714 moles x 4.00 grams = 10.856 grams

According to the number of significant figures, 2.714 moles of helium has a mass of 10.9 grams (exact value: 10.856 grams).

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What volume of air at 25°C and 1.00 atm can he stored in a 10.0 L high-pressure air tank if compressed to 25°C and 175 atm?
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Explanation:

Given

Initial Temperature = 25°C

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Final Temperature = 25°C

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This question is an illustration of ideal gas law.

From the given parameters, the initial temperature and final temperature are the same; this implies that the system has a constant temperature.

As such, we'll make use of Boyle's Law to solve this;

Boyle's Law States that:

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While V₁ and V₂ represent Initial and final volume

The equation becomes

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1750 atm L = 1 atm * V₂

1750 L = V₂

Hence, the final volume that can be stored is 1750L

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