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Alex787 [66]
4 years ago
6

The cell membrane that surrounds the cell acts as a _____.

Chemistry
1 answer:
kicyunya [14]4 years ago
5 0

Answer: Option B

Explanation:

Cell membrane can be defined as the outermost covering of the cell which allows the movement of particles across membrane. The particles are allowed to move from inside of the cell to the outside of the cell and from outside to inside of the cell.

This kind of a membrane is known as selectively permeable which allows the movement of certain molecules only.

hence, the correct answer is option B

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Explanation:

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What is the molarity of a solution that is composed of 10 grams of Sodium Chloride ( NaCl) dissolved in 3.50 L of water
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<u>Answer:</u> The molarity of solution will be 0.049 M

<u>Explanation:</u>

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

\text{Molarity of solution}=\frac{\text{Given mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (L)}}

We are given:

Given mass of sodium chloride = 10 g

Molar mass of sodium chloride = 58.44 g/mol

Volume of solution = 3.50 L

Putting values in above equation:

\text{Molarity of NaCl}=\frac{10 g}{58.44g/mol\times 3.50}\\\\\text{Molarity of NaCl}=0.049M

Hence, the molarity of solution will be 0.049 M

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3 years ago
A lab scientist cools a liquid sample of water (2.6 kg) at 0.00°C to -192°C. The water turns to ice as this temperature change o
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<u>Answer:</u> The heat released for the given process is -1892 kJ

<u>Explanation:</u>

The processes involved in the given problem are:

1.)H_2O(l)(0^oC,273K)\rightarrow H_2O(s)(0^oC,273K)\\2.)H_2O(s)(0^oC,273K)\rightarrow H_2O(s)(-192^oC,81K)

Pressure is taken as constant.

To calculate the amount of heat released at same temperature, we use the equation:

q=m\times L_{f,v}       ......(1)

where,

q = amount of heat released = ?

m = mass of water/ice

L_{f,v} = latent heat of fusion or vaporization

To calculate the amount of heat released at different temperature, we use the equation:

q=m\times C_{p,m}\times (T_{2}-T_{1})        .......(1)

where,

q = amount of heat released = ?

C_{p,m} = specific heat capacity of medium

m = mass of water/ice

T_2 = final temperature

T_1 = initial temperature

Calculating the heat absorbed for each process:

  • <u>For process 1:</u>

Converting the latent heat of fusion in J/kg, we use the conversion factor:

1 kJ = 1000 J

So, (\frac{-334kJ}{1kg})\times (\frac{1000J}{1kJ})=-334\times 10^3J/kg

We are given:

m=2.6kg\\L_f=-334\times 10^3J/kg

Putting values in equation 1, we get:

q_1=2.6kg\times (-334\times 10^3J/kg)=-868400J

  • <u>For process 2:</u>

We are given:

m=2.6kg\\C_{p,s}=2050J/kg.K\\T_1=273K\T_2=81K

Putting values in equation 2, we get:

q_2=2.6kg\times 2050J/kg.K\times (81-(273))^oC\\\\q_2=1023360J

Total heat absorbed = q_1+q_2

Total heat absorbed = [-868400+(-1023360)]J=-1891760J=-1891.76kJ\approx -1892kJ

Hence, the heat released for the given process is -1892 kJ

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<span>Kind of substance besides water:
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