A cannon shell is fired straight up from the ground at an initial speed of 225 m/s. After how much time is the shell at a height
1 answer:
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Answer:
38.5 N/C
Explanation:
The electric field generated by a charged sphere at a point outside the sphere is equivalent to the electric field generated by a single point charge, and it is given by
where
is the Coulomb's constant
Q is the net charge
r is the distance from the centre of the sphere
In this problem, we have
Substituting into the equation, we find
Answer:
v = 0.5 [m/s]
Explanation:
In order to determine the speed in such a time interval, we must calculate the slope between the last two positions.
The slope of a line is determined by the following mathematical expression.
P₂ = point 2 = (12,12) = (x₂,y₂)
P₁ = Point 1 = (6,9) = (x₁,y₁)
In this specific case, we must see that in the x-axis we have time, and on the y-axis, we have the space axis.
Now using the slope:
This slope is equal to the speed (velocity)
v = 0.5 [m/s]