Ask question

Ask question

All categories

2 years ago

14

What is the actual yield if I reacted 100.0 g of uranium with excess bromine (uranium is the limiting reactant) and had an 83% y

ield?

1 answer:

rjkz [21]2 years ago

6 0

Answer:

83 grams of uranium brainliest plz

You might be interested in

Practice entering numbers that include a power of 10 by entering the diameter of a hydrogen atom in its ground state, dH=1.06×10

kkurt [141]

Answer:

The diameter of the hydrogen $\mathbf{d =1.0605 \times 10^{-10}\ m}$

Explanation:

From the given information:

Using the concept of Bohr's Model, the equation for the angular momentum can be expressed as:

$L = \dfrac{nh}{2 \pi}$

Where the generic expression for angular momentum is:

L = mvr.

replacing the value of L into the previous equation, we have:

$mvr= \dfrac{nh}{2 \pi}$

$v= \dfrac{nh}{2 \pi mr}$ ----- (1)

The electron in the hydrogen atom posses an electrostatic force which gives a centripetal force.

$\dfrac{ke^2}{r^2} = \dfrac{mv^2}{r}$ ----- (2)

replacing the value of v in equation (1) into (2), and taking r as the subject of the formula, we have:

$\dfrac{ke^2}{r} = m (\dfrac{nh}{2 \pi mr})^2$

$ke^2=\dfrac{n^2h^2}{4 \pi^2 mr}$

$r =\dfrac{n^2h^2}{4 \pi^2 mke^2}$

For ground-state n = 1

$h = (6.625 \times 10^{-34} \ J.s)^2$

$m =( 9.1 \times 10^{-31} \ kg)(9 \times 10^9 \ N .m^2/C^2)$

$Ke = (1.6 \times 10^{-19} \ C)^2$

$r =\dfrac{(1)^2(6.625 \times 10^{-34})^2}{4 \pi^2 (9.1 \times 10^{-31} )(9 \times 10^9 ) (1.6 \times 10^{-19})^2}$

$r =\dfrac{4.3890625 \times 10^{-67}}{8.27720295 \times 10^{-57}}$

$\mathbf{r = 5.3025 \times 10^{-11} \ m}$

Therefore, the diameter of hydrogen d = 2r

$\mathbf{d = ( 2 \times 5.3025 \times 10^{-11} \ m})}$

$\mathbf{d =1.0605 \times 10^{-10}\ m}}$

4 0

2 years ago

If an object absorbs light energy it's thermal energy ______ .

kolezko [41]

It would be probably most likely B

3 0

2 years ago

A hydraulic system is designed to lift cars for inspection in a service station. The narrow end of the system has a surface area

fiasKO [112]

<u>Given:</u>

Surface area at the narrow end, A1 = 5.00 cm2

Force applied at the narrow end, F1 = 81.0 N

Surface area at the wide end, A2 = 725 cm2

<u>To determine:</u>

Force F2 applied at the wide end

<u>Explanation:</u>

Use the relation

F1/A1 = F2/A2

F2 = F1*A2/A1 = 81.0 N * 725 cm2/5.00 cm2 = 11,745 N

Ans: (b)

The force applied at the wide end = 11,745 N

5 0

2 years ago

Read 2 more answers

A carbene is a highly reactive intermediate in which a carbon atom bears a lone pair and no formal charge: how many hydrogen ato

Colt1911 [192]

Carbene is :CH₂ (i.e, methylene) which contains one neutral divalent carbon atom with valency of two and two unshared valence electrons. Carbene is of two types: Singlet carbene and Triplet carbene. Carbenes are very short lived and unstable. It is highly reactive intermediate. General carbene which refers to specific species methylene ( :CH₂) contains two hydrogen atoms. Carbene is one of the very important intermediate of various organic synthesis.

4 0

2 years ago

14. Which of the following is true of the nucleus?

velikii [3]

A)
Because it does not contain exactly all the DNA in the cell and some cells don't have a nucleus٫ such as the red blood cells.

5 0

2 years ago