Answer:
Explanation:
The momentum of the 25 kg mass is


If this whole momentum of the object is transferred to the 5.0 kg object then according to the law of conservation of momentum, the momentum of the 25.0 kg object must be transferred to the 5.0 kg object:



Answer:
4v/3
Explanation:
Assume elastic collision by the law of momentum conservation:

where v is the original speed of car 1, v1 is the final speed of car 1 and v2 is final speed of car 2. m1 and m2 are masses of car 1 and car 2, respectively
Substitute 

Divide both side by
, then multiply by 6 we have



So the final speed of the second car is 4/3 of the first car original speed
propagated disturbance is a variation
I Think Its True My Dude Or Dudette
.
Hope this helps
.
Zane
Answer:
C
Explanation:
Because this same question was on my test last week and I got it correct