Why are environmental factors important to consider when assessing an individual’s health?

Chemistry

2 answers:

lisabon 2012 [21]3 years ago

3 0

Answer: c. Some health risks are increased by heredity, which manifest under certain environmental conditions.

Explanation:

Many abiotic factors (non-living factors) such as radiations, hazardous substances present in the environment such as air, water and soil may originate from the industries, mining practices, fossil fuels and landfills. Some of the substances are carcinogenic and mutagenic in nature. These are capable of affecting the genetic make up of the organism. The genetic variations or mutations occurs may transmit from the parent to the offsprings.

Therefore, on the basis of the above information, c. Some health risks are increased by heredity, which manifest under certain environmental conditions. is the correct option.

cupoosta [38]3 years ago

3 0

Answer: C:Some health risks are increased by heredity, which manifest under certain environmental conditions.

Explanation:

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Chloroform is an excellent solvent for extracting caffeine from water. The distribution coefficient, KD, (Cchloroform/Cwater) fo

Art [367]

The relative volumes of chloroform and water that should be used is 9:10

Concentration of solution in chloroform = $90$ ( moles of chloroform )

Concentration of solution in water = $10$ ( moles of water )

Dissociation constant at $25^oC$ ; $K_D = 10$

$K_D =$ Concentration of solution in chloroform / Concentration of solution in water

Meaning;

$K_D = \frac{\frac{mole\ of\ chloroform}{volume\ of\ chloroform} }{\frac{mole\ of\ water}{volume\ of\ water} }$

Since $90$ mole is present in chloroform and $10$ mole is present in water, Total mole of Caffeine present is $100$

Now, we substitute our given values into the equation

$10 = \frac{\frac{90}{volume\ of\ chloroform} }{\frac{10}{volume\ of\ water} }\\\\10 *\frac{10}{volume\ of\ water} = \frac{90}{volume\ of\ chloroform} \\\\\frac{100}{volume\ of\ water} = \frac{90}{volume\ of\ chloroform}\\\\\frac{volume\ of\ chloroform}{volume\ of\ water} = \frac{90}{100}\\\\ \frac{volume\ of\ chloroform}{volume\ of\ water} = \frac{9}{10}\\\\ \frac{volume\ of\ chloroform}{volume\ of\ water} = 9:10$