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emmasim [6.3K]
3 years ago
5

How many carbon atoms are present in a 10.0g sample of C3H8

Chemistry
2 answers:
balu736 [363]3 years ago
4 0

Answer:

4.09ₓ10²³ atoms are contained in 10g of C₃H₈

Explanation:

1 mol of C₃H₈ has 3 mol of carbon and 8 mol of hydrogen.

1 mol of C₃H₈ weighs 44 g

In 44 g of C₃H₈ we have 3 mol of C

In 10 g of C₃H₈ we'll have (10 . 3)/ 44 = 0.681 mol

1 mol of C has NA (6.02x10²³) particles

0.681 mol will have (0.681 . 6.02x10²³) = 4.09ₓ10²³ atoms

gayaneshka [121]3 years ago
4 0

Answer:

There are  4.1 *10^23 carbon atoms in 10.0 grams of C3H8

Explanation:

Step 1: Data given

Mass of C3H8

Molar mass of C3H8 = 44.1 g/mol

Number of Avogadro = 6.022 *10^23 / mol

Step 2: Calculate number of moles

Number of moles = mass / molar mass

Number of moles C3H8 = 10.0 grams / 44.1 g/mol

Number of moles C3H8 = 0.227 moles

Step 3: Calculate number moles of carbon

For 1 mol C3H8 we have 3 moles of carbon

For 0.227 moles of C3H8 we have 3*0.227 = 0.681 moles

Step 4: Calculate number of carbon atoms

Number of carbon atoms = 0.681 moles * 6.022 *10^23

Number of carbon atoms = 4.1 * 10^23 carbon atoms

There are  4.1 *10^23 carbon atoms in 10.0 grams of C3H8

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Pete Gannett

 · 

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Ph.D. Chemistry, University of Wisconsin-Madison, (1982)2y

Seems to be an ideal gas law question. The relevant equation is:

PV = nRT

where P is the pressure in atmospheres, V is the volume in liters, n is the number of moles of gas, R is the gas constant (0.082 atm-L/mole-deg K), and T is temperature in Kelvins. STP means standard temperature and pressure and this is taken as 1 atm and 0º C or 273 K.

To calculate the number of molecules we will use the constant 6.023 * 10^23 molecules/mole and, therefore, we will need to know the number of moles (n). So, first we’ll rearrange the gas law equation, isolating ’n’ and then put the numbers in.

n = PV/RT = 1 * 1 / (0.082)(273) = 0.0447 moles

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# molecules of nitrogen in 1 Liter at STP = 6.023 * 10^23 molecules/mole * 0.0447 moles = 2.6905 * 10^22 molecules

Note, it does not matter what the gas is.

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