Question

A 100-g toy car moves along a curved frictionless track. At first, the car runs along a flat horizontal segment with an initial velocity of 3.33 m/s. The car then runs up the frictionless slope, gaining 0.108 m in altitude before leveling out to another horizontal segment at the higher level. What is the final velocity of the car if we neglect air resistance

Answer 1

Answer:

2.994 m/s

Explanation:

m = Mass of the car = 100 g

$v_1$ = Initial velocity = 3.33 m/s

h = Height = 0.108 m

g = Acceleration due to gravity = 9.81 m/s²

We know that energy in the system is conserved so

$\dfrac{1}{2}mv_1^2=mgh+\dfrac{1}{2}mv_f^2\\\Rightarrow v_f=\sqrt{2\left({\dfrac{1}{2}v_1^2-gh}\right)}\\\Rightarrow v_f=\sqrt{2\left(\dfrac{1}{2}3.33^2-9.81\times 0.108\right)}\\\Rightarrow v_f=2.994\ m/s$

The final velocity of the car is 2.994 m/s