Answer:
Galileo called the dark spots on the sun sunspots.
1). Force = (mass) x (acceleration)
Force = (20 kg) x (0.5 m/s )
Force = <em>10 Newtons</em>
2). Force = (mass) x (acceleration)
In this case, the acceleration is the acceleration of gravity.
1 N = (mass) x (9.8 m/s )
Mass = (1 N) / (9.8 m/s )
Mass = <em>0.1 kg</em>
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3). Force = (mass) x (acceleration)
This formula is important. Memorize it !
You saw here that the same formula answered both of your questions.
It'll answer a lot more Physics questions that you haven't seen yet.
If you're taking a Physics class, there will DEFINITELY be at least one question on the final exam that will test you to see whether you know this formula and how to use it. Maybe more than one.
Answer:
A) τ = 1,222 10⁻⁶ N m
, B) w = 0.24 rad / sec
, v = 2.88 10⁻³ m / s
Explanation:
Part A
We can get the torque
τ= F x r
bold are vector
τ = F r sin θ
Let's use according to Newton's law
F - W = 0
F = mg
τ = mg r sin θ
Let's reduce the magnitudes to the SI system
m = 12 ug = 12 10⁻⁶ kg
r = 12 mm = 12 10⁻³ m
Let's calculate
τ = 12 10⁻⁶ 9.8 12 10⁻³ sin 60
τ = 1,222 10⁻⁶ N m
Part B
Let's use Newton's law for rotational movement
τ = I α
The moment of inertia of the antero that we approximate as a particle is
τ = m r² α
α = τ / m r²
α = 1,222 10⁻⁶ / (12 10⁻⁶ (12 10⁻³)²)
α = 0.70718 10³ rad / s²
Angular velocity is
w = w₀ + α t
w = 0 + 0.70718 10³ 0.34 10⁻³
w = 0.24 rad / sec
Angular and linear variables are related.
v = w r
v = 0.24 12 10⁻³
v = 2.88 10⁻³ m / s
Answer:
The frequency of the sound wave in the helium in the stopped pipe is 749.25 Hz.
Explanation:
Given that,
Length = 1.00 m
Temperature T = 20°C
Speed of sound = 999 m/s
We need to calculate the frequency of the sound wave in the helium in the stopped pipe
Using formula of frequency
Put the value into the formula
Hence, The frequency of the sound wave in the helium in the stopped pipe is 749.25 Hz.