Answer:
electromagnetic wave. this energy is what lights the bulb.
Explanation:
When you close an electrical circuit, the electrons have a small drag speed, but the fluctuation of the electric field that is created originates by Lenz's law a magnetic field and the appearance of this magnetic field creates a fluctuating elective field, these two fields together forms a wave called an electromagnetic wave.
This electromagnetic wave has a speed given by the relation
v = √1 /ε μ
in a vacuum this speed is equal to the speed of light, which is worth 3 10⁸ m/s this very high value so the energy transported by this wave can travel the distance of 10 m in less than 10⁻⁷ s, This energy is what lights the bulb.
Answer: chemical; mechanical
Explanation:
Elastic collision is said to occur if the total kinetic energy is not conserved and if there is a rebound after collision
Step one
Analysis of the problem
Immediately after impact the car's velocity was zero making it a perfect elastic collision
Step two
Given
Mass of car M1=1800kg
Mass of truck M2=5200kg
Initial velocity of Car U1=44m/s
Initial velocity of truck U2=21m/s
Final velocity of car V1= 0m/s
Final velocity of truck V2=20m/s
Step three
According to the principle of conservation of momentum
Total momentum before collision
=M1U1+M2U2
Total momentum after impact
=M1V1+M2V2
M1U1+M2U2 =M1V1+M2V2
Substituting our data into the expression we have 1500*44+5800*21=1500*0+5800*20
=66000+1218000=11600
1284000=11600
From the solution the momentum before impact is 1284000Ns
Momentum after impact is 11600Ns
This is indicating that after impact there was loss in momentum as a result of the car having a velocity of zero
Answer:
Explanation:
No, the bungee jumper is not at equilibrium.
This can be explained when we consider a bungee jumper as a mass that is undergoing simple harmonic motion. At extreme points i.e. at the bottom, the velocity of the jumper is zero but not the acceleration because it is acting in the opposite direction that is why the jumper moves upward.
The image height is -10 cm (the image is upside down)
Explanation:
We can solve the problem by using the mirror equation:

where:
f = 5 cm is the focal length of the mirror
p = 10 cm is the distance of the object from the mirror
q is the distance of the image from the mirror
Solving for q, we find:

So, the distance of the image from the mirror is 10 cm.
Now we can find the image height by using the magnification equation:

where
y' is the height of the image
y = 1 cm is the height of the object
and using
p = 10 cm
q = 10 cm
We find the size of the image:

where the negative sign indicates that the image is upside down.
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