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sesenic [268]
3 years ago
15

Certain materials can become superconductors under what conditions?

Physics
1 answer:
tresset_1 [31]3 years ago
6 0

Option (b) is correct. The certain materials can act as superconductors at a very low temperature.

Explanation:

The Superconductivity of a material is the property of the particular substance to provide no resistance to the path of the current through it. The current does not face any hindrance due to the motion of the other particles inside the conductor.

The superconductivity of a substance leads to the flow of current through the substance or the material without any hindrance. The resistance of a substance is due to the motion of the particles inside it. If all the motion occurring inside the substance are seized, there will be no resistance offered by the conductor.

Therefore, the superconductivity can be defined as the state where all the motions inside the a material are seized. This occurs at a very low temperature. The absolute zero temperature(0\text{ K or }-273^\circ\text{ C}) is regarded as the temperature where there is no motion in any particle.

Thus, Option (b) is correct. The certain materials can act as superconductors at a very low temperature.

Learn More:

1. An electrical shock happens when electric brainly.com/question/3059888

2.  A capacitor with capacitance (c) = 4.50 μf is connected to a 12.0 v battery brainly.com/question/8892837

3. Reason for the difference in resistance of bulb brainly.com/question/10421964

Answer Details:

Grade: High School

Subject: Physics

Chapter: Conductivity

Keywords:

material, superconductor, motion, pressure, cold, temperature, substance, material, conditions, superconductivity.

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lbvjy [14]

The equation 15v_{i} + 2*0 = (15 + 2)v_{f} (option 3) represents the horizontal momentum of a 15 kg lab cart moving with a constant velocity, v, and that continues moving after a 2 kg object is dropped into it.  

The horizontal momentum is given by:

p_{i} = p_{f}

m_{1}v_{1}_{i} + m_{2}v_{2}_{i} = m_{1}v_{1}_{f} + m_{2}v_{2}_{f}

Where:

  • m₁: is the mass of the lab cart = 15 kg
  • m₂: is the <em>mass </em>of the object dropped = 2 kg
  • v_{1}_{i}: is the initial velocity of the<em> lab cart </em>
  • v_{2}_{i}: is the <em>initial velocit</em>y of the <em>object </em>= 0 (it is dropped)
  • v_{1}_{f}: is the final velocity of the<em> lab cart </em>
  • v_{2}_{f}: is the <em>final velocity</em> of the <em>object </em>

Then, the horizontal momentum is:

15v_{1}_{i} + 2*0 = 15v_{1}_{f} + 2v_{2}_{f}

When the object is dropped into the lab cart, the final velocity of the lab cart and the object <u>will be the same</u>, so:

15v_{1}_{i} + 2*0 = v_{f}(15 + 2)

Therefore, the equation 15v_{i} + 2*0 = (15 + 2)v_{f} represents the horizontal momentum (option 3).

Learn more about linear momentum here:

  • brainly.com/question/2141713?referrer=searchResults
  • brainly.com/question/2400186?referrer=searchResults

I hope it helps you!            

4 0
2 years ago
Write short letters.
Svetradugi [14.3K]

Answer:

No. 67

Peter Street

12th Road

Chennai

24th June 201_

Dear Amrish

I have come to know that since your school has closed for the Autumn Break you have plenty of free time at your disposal at the moment. I would like to tell you that even I am having holidays now.

It has been a long time since we have spent some time together. If you are free, I would welcome to have your company this weekend. Why don’t you come over to my house and spend a day or so with me?

I am anxiously waiting for your reply.

Yours affectionately

your name

4 0
2 years ago
Read 2 more answers
What must happen to an atom of magnesium in order to become a magnesium ion Mg+2?
igomit [66]

Answer:

Answer is: c. It must lose two electrons and become an ion.

Magnesium (Mg) is metal from 2. group of Periodic table of elements and has low ionisation energy and electronegativity, which means it easily lose valence electons (two valence electrons).

Magnesium has atomic number 12, which means it has 12 protons and 12 electrons. It lost two electrons to form magnesium cation (Mg²⁺) with stable electron configuration like closest noble gas neon (Ne) with 10 electrons.

Electron configuration of magnesium ion: ₁₂Mg²⁺ 1s² 2s² 2p⁶.

Explanation:

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Move from higher to lower energy levels
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