Change in momentum over time.
Answer:
E. 0.25
Explanation:
Given that
Angular speed ω = 3.5 rad/s
Distance ,r= 0.2 m
Lets take mass of dust bunny = m
We know that
Radial force F = m ω² r
The friction force on the dust bunny Fr
Fr= μ m g
To getting slung off dust bunny from disk
m ω² r = μ m g
ω² r = μ g
3.5² x 0.2 = μ x 10 ( take g =10 m/s²)
μ = 0.245
μ = 0.25
Therefore answer is E
E. 0.25
Answer:
The acceleration of the electron is 1.457 x 10¹⁵ m/s².
Explanation:
Given;
initial velocity of the emitted electron, u = 1.5 x 10⁵ m/s
distance traveled by the electron, d = 0.01 m
final velocity of the electron, v = 5.4 x 10⁶ m/s
The acceleration of the electron is calculated as;
v² = u² + 2ad
(5.4 x 10⁶)² = (1.5 x 10⁵)² + (2 x 0.01)a
(2 x 0.01)a = (5.4 x 10⁶)² - (1.5 x 10⁵)²
(2 x 0.01)a = 2.91375 x 10¹³

Therefore, the acceleration of the electron is 1.457 x 10¹⁵ m/s².