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Vsevolod [243]
3 years ago
5

Which scenario would result in a positive population growth? Use this formula: population growth = (birth rate + immigration) –

(death rate + emigration)
A. 30 individuals emigrate, 30 individuals die, 30 individuals are born, 0 individuals immigrate
B. 22 individuals emigrate, 10 individuals are born, 12 individuals immigrate, 0 individuals die
C. 15 individuals immigrate, 9 individuals emigrate, 6 individuals are born, 0 individuals die
D. 18 individuals immigrate, 20 individuals die, 1 individual is born, 0 individuals emigrate
Physics
2 answers:
RSB [31]3 years ago
5 0

Answer:

c.  I got it right on Edge

Bas_tet [7]3 years ago
3 1

B?

no one dies, just people moving and being born

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Buoyancy increases with the increase in the density of a) Submerged body b) Fluid​
AlekseyPX

Answer:

Submerged body

Explanation:

  • If buoyancy is greater than weight then object will float.
  • If buoyancy is less then weight then object will sink.
  • If buoyancy=weight then objects remains stable
4 0
3 years ago
Two sealed 1 l containers full of gas are at room temperature. Container a has a pressure of 4 atm and container b has a pressur
loris [4]

Answer:

The number density of the gas in container A is twice the number density of the gas in container B.

Explanation:

Here we have

P·V =n·R·T

n = P·V/(RT)

Therefore since V₁ = V₂ and T₁ = T₂

n₁ = P₁V₁/(RT₁)

n₂ = P₂V₂/(RT₂)

P₁ = 4 atm

P₂ = 2 atm

n₁ = 4V₁/(RT₁)

n₂ =2·V₁/(RT₁)

∴ n₁ = 2 × n₂

Therefore, the number of moles in container A is two times that in container B and the number density of the gas in container A is two times the number density in container B.

This can be shown based on the fact that the pressure  of the container is due to the collision of the gas molecules on the walls of the container, with a kinetic energy that is dependent on temperature and mass, and since the temperature is constant, then the mass of container B is twice that of A and therefore, the number density of container A is twice that of B.

5 0
3 years ago
A particle travels clockwise on a circular path of diameter​ R, monitored by a sensor on the circle at point​ P; the other endpo
kotykmax [81]

We make a graphic of this problem to define the angle.

The angle we can calculate through triangle relation, that is,

sin\theta = \frac{c}{QP}\\sin\theta = \frac{c}{R}\\\theta=sin^{-1}\frac{c}{R}

With this function we should only calculate the derivate in function of c

\frac{d\theta}{dc} = \frac{1}{\sqrt{1-\frac{c^2}{R^2}}}(\frac{c}{R})'\\\frac{d\theta}{dc} = \frac{1}{\sqrt{R^2-c^2}}

That is the rate of change of \theta.

b) At this point we need only make a substitution of 0 for c in the equation previously found.

\frac{d\theta}{dc}\big|_{c=0} = \frac{1}{\sqrt{R^2-0}}\\\frac{d\theta}{dc}\big|_{c=0} = \frac{1}{R}

Hence we have finally the rate of change when c=0.

6 0
3 years ago
Suppose the electrostatic force between two electrons is F. What is the electrostatic force between an electron and a proton
mars1129 [50]

Answer:

D. −F

Explanation:

the rest of the answers are

2/3F

The force is represented as a positive quantity and is repulsive.

Electrostatic force is inversely proportional to the square of the distance.

The direction of the force changes, and the magnitude of the force quadruples.

hope this helps sorry if i was too late! :)

8 0
3 years ago
An object moves uniformly around a circular path of radius 19.0 cm, making one complete revolution every 2.40 s.
klio [65]

Answer:

v = 0.5 m/s

f = 0.42 Hz

ω = 2.6 rad/sec

Explanation:

  • By definition, the translational speed is the rate of change of the position with respect to time.
  • The change in position along a complete revolution is just the following:
  • Δs = 2*π*r = 2*π*0.19 m = 1.19 m
  • The time needed to complete a revolution is 2.4 s, so the translational speed can be written as follows:

        v =\frac{\Delta s}{\Delta t} = \frac{1.19m}{2.4s} = 0.5 m/s (1)

  • The frequency in Hz is just the inverse of the time needed to complete a revolution (known as the period T), as follows:
  • f = 1/T = 1/2.4s = 0.42 Hz (2)
  • Finally, the angular speed is the rate of change of the angle rotated with respect to time, as follows:

       \omega = \frac{\Delta\theta}{\Delta t} =  \frac{2*\pi}{2.4s} = 2.6 rad/sec (3)

5 0
3 years ago
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