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Ludmilka [50]
3 years ago
14

Please please please help

Chemistry
1 answer:
weqwewe [10]3 years ago
3 0

Answer:

See explanation.

Explanation:

Hello!

In this case, since the main molecular reaction that is taken place in the beaker is:

AgNO_3(aq)+BaI_2(aq)\rightarrow AgI(s)+Ba(NO_3)_2(aq)

In such a way, we understand that one breaker contained silver nitrate and the other one barium iodide. Thus, the complete molecular equations turns out:

2AgNO_3(aq)+BaI_2(aq)\rightarrow 2AgI(s)+Ba(NO_3)_2(aq)

Now, for the complete ionic equation, we just ionize the aqueous species:

2Ag^++2NO_3^-+Ba^{2+}+2I^-\rightarrow 2AgI(s)+Ba^{2+}+2(NO_3)^-

Finally, for the net ionic equation we cancel out barium and nitrate ions as the spectator one because they are both sides on the equation:

2Ag^++2I^-\rightarrow 2AgI(s)

Best regards!

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