Question

Please please please help

Answer 1

Answer:

See explanation.

Explanation:

Hello!

In this case, since the main molecular reaction that is taken place in the beaker is:

$AgNO_3(aq)+BaI_2(aq)\rightarrow AgI(s)+Ba(NO_3)_2(aq)$

In such a way, we understand that one breaker contained silver nitrate and the other one barium iodide. Thus, the complete molecular equations turns out:

$2AgNO_3(aq)+BaI_2(aq)\rightarrow 2AgI(s)+Ba(NO_3)_2(aq)$

Now, for the complete ionic equation, we just ionize the aqueous species:

$2Ag^++2NO_3^-+Ba^{2+}+2I^-\rightarrow 2AgI(s)+Ba^{2+}+2(NO_3)^-$

Finally, for the net ionic equation we cancel out barium and nitrate ions as the spectator one because they are both sides on the equation:

$2Ag^++2I^-\rightarrow 2AgI(s)$

Best regards!