Question

If atoms in a regular three-dimensional solid are about 10−10m apart, what is the orderof magnitude estimate of the number of atoms in a cube with sides of length 10−2m?(Enter the exponentnfrom your answer of 10n.)(a) 36(b) 24(c) 12(d) 8

Answer 1

Answer:

(b) 24

Explanation:

Given that:

If atoms in a regular three-dimensional solid are about 10⁻¹⁰ m apart:

Then; the volume of the atom will be (10⁻¹⁰ m)³

= (10⁻³⁰ m)

Since, we were told that the cube have length 10⁻² m .; its volume will also be

= (10⁻² m) ³

= (10⁻⁶ m)

Now, the estimate of the number of atoms in the cube can now be:

$N_A=\frac{V_{cube}}{V_{atom}}$

= $\frac{10^{-6}}{10^{-30}}$

= 10²⁴

So,we can therefore conclude that our answer is 10²⁴  (Since we are asked to enter it in exponential form)