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Feliz [49]
3 years ago
5

A man has 43 coins, All nickels, dimes & quarters. He has one more  than three times as many dimes as he does nickels and tw

ice as many quarters as he does nickels.
How many of each coin does he have ?
Mathematics
1 answer:
a_sh-v [17]3 years ago
5 0
1 + 3d = n   =>  (n-1) / 3 = d
2n = q
n + d + q = 43
substitute
n + (n-1) / 3 + 2n = 43
n = 13
q = 26
d = 4

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