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Fynjy0 [20]
3 years ago
8

Understanding the high-temperature behavior of nitrogen oxides is essential for controlling pollution generated in automobile en

gines. The decomposition of nitric oxide (no) to n2 and o2 is second order with a rate constant of 0.0796 m−1⋅s−1 at 737∘c and 0.0815 m−1⋅s−1 at 947∘c. You may want to reference (page) section 14.5 while completing this problem. Part a calculate the activation energy for the reaction. Express the activation energy in kilojoules per mole to three significant digits.
Chemistry
1 answer:
disa [49]3 years ago
6 0

Hey there!

Arrhenius equation :

k = A exp ( -Ea/ RT )

ln ( K2 / K1 ) =  ( -Ea/ R ) * ( 1 / T2 - 1 / T1 )

K1 = 0.0796 m⁻¹s⁻¹

K2 = 0.0815 m⁻¹s⁻¹

T1 = 737 ºC  = 737 + 273.15 => 1010.15 K

T2 = 947ºC = 947 + 273.15 => 1220.15 K

R =  8.314 J / mol*K

ln (  0.0815 / 0.0796 ) =  ( -Ea / 8.314 ) *  ( 1 / 1220.15  -  1 / 1010.15 )

Activation energy  Ea =  1151 J / mol ≈  1.15 Kj/mol

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ch sulfide (ZnS) occurs in the zinc blende crystal structure, (a) If 254 g of ZnS contains 170 g of Zn, what is the mass ratio o
Aleonysh [2.5K]

Answer:

The mass ratio of zinc to sulfide is 85:42.

2.5559 kg of Zn are in 3.82 kg of ZnS.

Explanation:

a) Mass of zinc sulfide = 254 g

Mass of zinc in a zinc sulfide sample = 170 g

Mass of sulfide in zinc sulfide sample = x

254 g = 170 g+ x

x = 84 g

The mass ratio of zinc to sulfide:

\frac{170 g}{84 g}=\frac{85}{42}

b) Mass of zincsulfide sample = 3.83 kg

The mass ratio of zinc to sulfide is 85:42.

Let the mass of zinc and sulfide be 85x and 42x respectively:

85 x+ 42 x=3.82 kg

x =0.03007 kg

Mass of an zinc= 85x=85 × 0.03007 kg= 2.5559 kg

8 0
3 years ago
A potassium-40 sample starts with 50 atoms, and 1.25 billion years later, there are 25 atoms. What is the half-life of potassium
guapka [62]
D. 1.25 billion years
5 0
3 years ago
What volume of 0.4567 m h2so4 is required to neutralize 30.00 ml of 0.3210 m naoh?
sertanlavr [38]
Answer is: volume of H₂SO₄ is 42.1 mL.<span>
Chemical reaction: H</span>₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O.<span>
c(H</span>₂SO₄) = 0,4567 M = 0,4567 mol/L.<span>
V(NaOH) = 30 mL </span>÷ 1000 mL/L <span>= 0,03 L.
c(NaOH) = 0,321 M = 0,321 mol/L.
n(NaOH) = c(NaOH) · V(NaOH).
n(NaOH) = 0,321 mol/L · 0,030 L.
n(NaOH) = 0,00963 mol.
From chemical reaction: n(H</span>₂SO₄) : n(NaOH) = 1 : 2.<span>
n(H</span>₂SO₄) = 0,01926 mol.<span>
V(H</span>₂SO₄) = n(H₂SO₄) ÷ c(H₂SO₄).<span>
V(H</span>₂SO₄) = 0,01926 mol ÷ 0,4567 mol/L.<span>
V(H</span>₂SO₄<span>) = 0,0421 L = 42,1 mL.</span>
3 0
3 years ago
Question 1(Multiple Choice Worth 4 points) (02.03 LC) A scientist studied four rock fossils that show evolution of the modern-da
ASHA 777 [7]

Answer:

The correct answer is 1 millon years.

Explanation:

Fossil rocks serve to study the evolution of species throughout history. Species usually adapt to survive the changing environment around them. Given this fact, we can deduce that the oldest species were very different from the way they are today. This means that the current species are more similar to those that preceded them more recently. The fossil of 1 million years ago is the most similar to today's horse.

Have a nice day!

3 0
3 years ago
Need answer to this question asap. it is worth 10 points
andrey2020 [161]

The molecular formula of the liquid​ : C₆H₁₂

<h3>Further explanation</h3>

Given

molar ratio C H = 1.2 : 0.12

0.12 g at STP gave 32 cm³(0.032 L)

Required

The molecular formula

Solution

At STP, 1 mol = 22.4 L, so for 0.032 L :

mol = 0.032 : 22.4

mol = 0.00143

Molar mass (M) of liquid :

M = mass : mol

M = 0.12 g : 0.00143 mol

M = 83.92≈84 g/mol

C : H = 1 : 2

(CH₂)n=84

(12+2.1)n=84

(14)n=84

n=6

(CH₂)₆=C₆H₁₂

3 0
2 years ago
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