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2 years ago

How is aluminum used in a lithium ion type of battery?

Chemistry

1 answer:

r-ruslan [8.4K]2 years ago

7 0

Answer:

Explanation:

Aluminium is used in rechargeable battery.

Aluminium ions provide the energy by flowing from anode to the cathode.

When the battery is recharged these ions comes to the anode.

The one ion gives three electrons. Which means one Al⁺³ is equal to the three Li⁺ ions. So, three unit of charge giving by ions increase the energy storage capacity.

The rechargeable batteries with aluminium gives low cost and low flammability.

It is safe to use because of inertness of aluminium and also easy to use in ambient environment.

Aluminium also have high volume capacity than lithium which means energy storage per volume is greater.

Its charge discharge cycles are also greater.

The aluminum ion batteries are also smaller in size.

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A solution at ph 10 contains __________ than the same amount of solution at ph 8.

Sindrei [870]

100 times less H+

A solution at ph 10 contains<u> </u><u>100 times less H+</u> than the same amount of solution at ph 8.

<h3>The pH scale: How does it function?</h3>

The pH scale determines how acidic or basic water is.
The range is 0 to 14, with 7 representing neutrality.
Acidity is indicated by pH values below 7, whereas baseness is shown by pH values above 7.
In reality, pH is a measurement of the proportion of free hydrogen and hydroxyl ions in water.

<h3>How does the pH change when two acids are combined?</h3>

An acid's strength increases with the quantity of hydrogen ions it releases.
The pH of the strong acids is between 1 and 2.
We may observe that there is no response when two acids of the same strength are combined.
It's because the end product will be neutral and the pH won't change.

<h3>How is pH value determined?</h3>

There are two ways to measure pH:

colorimetrically with indicator fluids or sheets
electrochemically with electrodes and a millivoltmeter for greater accuracy (pH meter).

To learn more about pH visit:

brainly.com/question/491373

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8 0

2 years ago

What is the mass of 0.28 mole of iron?

vredina [299]

Answer:

Your answer should be 15.68 grams.

Explanation:

Seeing as 1 mole has a mass of 56 g, 56*0.28 would get you 15.68 g.

6 0

3 years ago

PLEASE I NEED HELP ASAP

Murljashka [212]

Answer:

Because the density of water is one

4 0

3 years ago

Sugar dissolves readily in water because it is a(n) ____ substance.

Mnenie [13.5K]

The answer to this question would be D. Hydrophilic.

The word hydrophilic mean attracted by water. That means the molecule has a force to attract water molecule, thus be able to dissolve in water. The polarity of the molecule would determine whether a molecule hydrophilic or not.
Its opposite would be hydrophobic which the molecule can't dissolve in water. One example of this would be oil or fat. That is why sometimes it is called lipophilic too.

3 0

3 years ago

An aqueous CsCl solution is 8.00 wt% CsCl and has a density of 1.0643 g/mL at 20°C. What is the boiling point of this solution?

umka2103 [35]

<u>Answer:</u> The boiling point of solution is 100.53

<u>Explanation:</u>

We are given:

8.00 wt % of CsCl

This means that 8.00 grams of CsCl is present in 100 grams of solution

Mass of solvent = (100 - 8) g = 92 grams

The equation used to calculate elevation in boiling point follows:

$\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of pure solution}$

To calculate the elevation in boiling point, we use the equation:

$\Delta T_b=iK_bm$

Or,

$\text{Boiling point of solution}-\text{Boiling point of pure solution}=i\times K_b\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

where,

Boiling point of pure solution = 100°C

i = Vant hoff factor = 2 (For CsCl)

$K_b$ = molal boiling point elevation constant = 0.51°C/m

$m_{solute}$ = Given mass of solute (CsCl) = 8.00 g

$M_{solute}$ = Molar mass of solute (CsCl) = 168.4 g/mol

$W_{solvent}$ = Mass of solvent (water) = 92 g

Putting values in above equation, we get:

$\text{Boiling point of solution}-100=2\times 0.51^oC/m\times \frac{8.00\times 1000}{168.4g/mol\times 92}\\\\\text{Boiling point of solution}=100.53^oC$

Hence, the boiling point of solution is 100.53

6 0

3 years ago