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Solnce55 [7]
3 years ago
7

To be able to compete in a particular class, a bodybuilder can weigh in at no more than

Mathematics
1 answer:
adell [148]3 years ago
4 0

Answer:

Range of weight = 176 - 146 pound

Step-by-step explanation:

Given:

Maximum weight = 175 pound

Minimum weight = 145 pound

Clothes weight = 1 pound

Find:

Range of weight

Computation:

Range = maximum weight - 1 pound

Range = minimum weight + 1 pound

Range = 175 - 1 pound

Range = 145 + 1 pound

Range = 174

Range = 146

Range of weight = 176 - 146 pound

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A.1

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No other point is connect to those 4 lines

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3. Assume that the likelihood of a child under the age of ten watching PBS is 0.76. Three children are
natta225 [31]

Using the binomial distribution, the probabilities are given as follows:

a) 0.4159 = 41.59%.

b) 0.5610 = 56.10%.

c) 0.8549 = 85.49%.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

For this problem, the values of the parameters are:

n = 3, p = 0.76.

Item a:

The probability is P(X = 2), hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{3,2}.(0.76)^{2}.(0.24)^{1} = 0.4159

Item b:

The probability is P(X < 3), hence:

P(X < 3) = 1 - P(X = 3)

In which:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{3,3}.(0.76)^{3}.(0.24)^{0} = 0.4390

Then:

P(X < 3) = 1 - P(X = 3) = 1 - 0.4390 = 0.5610 = 56.10%.

Item c:

The probability is:

P(X \geq 2) = P(X = 2) + P(X = 3) = 0.4159 + 0.4390 = 0.8549

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

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2 years ago
I need your help ASAP!
slega [8]

Answer:

C.

Step-by-step explanation:

If 4ab+k=13 then k=13-4ab

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