Both AM and FM radio signals have the same of what.....

If you had 0.867 miles of salt, NaCI , in a 0.69 L solution, what would be the molarity

Eva8 [605]

Answer:

Approximately $1.3\; \rm mol \cdot L^{-1}$ . (Assuming that the question says $0.867$ moles of salt in this $0.69\; \rm L$ solution.)

Explanation:

The molarity of a solution gives the quantity of the solute in every unit volume of the solution. In this question:

Quantity of solute: $n(\text{solute})= 0.867\; \rm mol$ (with moles as the unit.)
Volume of solution: $V(\text{solution}) = 0.69\; \rm L$ (with liters as the unit.)

Note that in this question, liter is the unit for the volume of the solution. The molarity of the solution should thus give the amount of solute in every liter of the solution:

$\begin{aligned} c & = \frac{n(\text{solute})}{V(\text{solution})} \\ &= \frac{0.867\; \rm mol}{0.69\; \rm mol} \approx 1.3\; \rm mol \cdot L^{-1}\end{aligned}$ .

6 0

4 years ago

SO2+O2 SO3 how many moles of O2 needed to combust 100.0g of sulfur dioxide

Oksanka [162]

2SO2 + O2 ------> 2SO3

1) M(SO2)= 32.0 + 2*16.0 = 64 g/mol

2) 100.0 g SO2 * 1 mol SO2/64 g SO2 = 1.5625 mol SO2

3) 2SO2 + O2 ------> 2SO3

2 mol 1 mol

1.5625 mol x mol

x= 1.5625/2=0.78125 ≈ 0.7813 mol O2

Answer: 0.7813 mol O2.

6 0

3 years ago

What are the five steps a flavor chemist needs to review before starting a flavor project

Katyanochek1 [597]

Answer:

flavorists, work primarily in the food, beverage, pharmaceutical, cosmetic, and pet industries. They use scientific and analytical tools, along with creativity, to boost natural flavors and create new ones

5 0

3 years ago

An equilibrium mixture of PCl5(g), PCl3(g), and Cl2(g) has partial pressures of 217.0 Torr, 13.2 Torr, and 13.2 Torr, respective

djverab [1.8K]

Answer:

The new partial pressures after equilibrium is reestablished for $PCl_3$ :

$P_1'=6.798 Torr$

The new partial pressures after equilibrium is reestablished $Cl_2$ :

$P_2'=26.398 Torr$

The new partial pressures after equilibrium is reestablished for $PCl_5$ :

$P_3'=223.402 Torr$

Explanation:

$PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)$

At equilibrium before adding chlorine gas:

Partial pressure of the $PCl_3=P_1=13.2 Torr$

Partial pressure of the $Cl_2=P_2=13.2 Torr$

Partial pressure of the $PCl_5=P_3=217.0 Torr$

The expression of an equilibrium constant is given by :

$K_p=\frac{P_1}{P_1\times P_2}$

$=\frac{217.0 Torr}{13.2 Torr\times 13.2 Torr}=1.245$

At equilibrium after adding chlorine gas:

Partial pressure of the $PCl_3=P_1'=13.2 Torr$

Partial pressure of the $Cl_2=P_2'=?$

Partial pressure of the $PCl_5=P_3'=217.0 Torr$

Total pressure of the system = P = 263.0 Torr

$P=P_1'+P_2'+P_3'$

$263.0Torr=13.2 Torr+P_2'+217.0 Torr$

$P_2'=32.8 Torr$

$PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)$

At initail

(13.2) Torr (32.8) Torr (13.2) Torr

At equilbriumm

(13.2-x) Torr (32.8-x) Torr (217.0+x) Torr

$K_p=\frac{P_3'}{P_1'\times P_2'}$

$1.245=\frac{(217.0+x)}{(13.2-x)(32.8-x)}$

Solving for x;

x = 6.402 Torr

The new partial pressures after equilibrium is reestablished for $PCl_3$ :

$P_1'=(13.2-x) Torr=(13.2-6.402) Torr=6.798 Torr$

The new partial pressures after equilibrium is reestablished $Cl_2$ :

$P_2'=(32.8-x) Torr=(32.8-6.402) Torr=26.398 Torr$

The new partial pressures after equilibrium is reestablished for $PCl_5$ :

$P_3'=(217.0+x) Torr=(217+6.402) Torr=223.402 Torr$

5 0

3 years ago

Is this a scientific model? Use complete sentences to explain why or why not.

tensa zangetsu [6.8K]

Answer:

Yes it is a scientific model because it is an outlook of a winter outlook and winter is a season and a type of weather and weather is meteorology and meteorology is a type of science so yes it is a scientific model.

Explanation:

8 0

3 years ago