1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dominik [7]
3 years ago
13

What is a chemical property of the fruit shown above? A. The fruit can decompose. B. The fruit has a mass of 250 grams. C. The f

ruit is orange. D. The fruit is a solid.
Chemistry
2 answers:
saw5 [17]3 years ago
6 0

i think the best answer for this is B)


Karolina [17]3 years ago
6 0

Answer:

the answer  is B

Explanation:

You might be interested in
When elements form bonds, it changes their ______ properties.<br>The answer is..? ​
Arturiano [62]

Answer:

chemical and physical

6 0
3 years ago
1) Alarge doud of dust and gas spread out in a large area is
alexdok [17]

Answer:

D. nebula

Explanation:

Hope this helps

<3

8 0
2 years ago
What is the coordination number for each of the following complexes or compounds? [Co(NH3)4(H2O)2]3+ [Cr(EDTA)]− [Pt(NH3)4]2+ Na
Burka [1]

Answer:

[Co(NH₃)₄(H₂O)₂]³⁺: coordination number = 6.

[Cr(EDTA)]⁻: coordination number = 6.

[Pt(NH₃)₄]²⁺: coordination number = 4.

Na[Au(Cl)₂]: coordination number = 2.

Explanation:

  • [Co(NH₃)₄(H₂O)₂]³⁺:

In this complex, Co is bonded with 4 molecules of NH₃ (with 4 coordinate bonds, one bond for each molecule) and 2 molecules of H₂O (with 2 coordinate bonds, one bond for each molecule) forming the complex with 6 coordinate bonds.

∴ coordination number = 6.

  • [Cr(EDTA)]⁻:

In this complex, Cr is bonded with 1 molecules of EDTA (with 6 coordinate bonds, 4 O atoms and 2 N atoms in EDTA molecule).

∴ coordination number = 6.

  • [Pt(NH₃)₄]²⁺:

In this complex, Pt is bonded with 4 molecules of NH₃ (with 4 coordinate bonds, one bond for each molecule).

coordination number = 4.

  • Na[Au(Cl)₂]:

In this complex, Au is bonded with 2 atoms of Cl (with 2 coordinate bonds, one bond for each atom).

coordination number = 2.

3 0
3 years ago
Distinguish between kinetic energy<br> and poteintial energy-
topjm [15]

Answer:

kinetic energy is energy possessed due to its motion while potential energy is energy possessed by a body by virtue of its position relative to others

6 0
2 years ago
When preparing the diazonium salt, the solution is tested with potassium iodide-starch paper. a positive test is the immediate f
Dahasolnce [82]
KI-starch paper allows the detection of strong oxidizers such as nitrite. It is used here to control diazotization of 4-nitroaniline. Nitrite oxidizes potassium iodide in order to form elemental iodine which reacts with starch to a blue-violet complex. With KI-starch paper, enough sodium nitrite is added to produce nitrous acid, which <span>then will react with 4-nitroaniline to form a diazonium salt.</span>
8 0
3 years ago
Other questions:
  • What is the frequency of a wave traveling at 5,000 m/s with a wavelength of .002 m/cycle?
    10·1 answer
  • A chemistry graduate student is studying the rate of this reaction:
    5·1 answer
  • how many grams of ammonium sulfate can be produced if 60.0 mol of sulfuric acid react with an excess of ammonia?
    9·2 answers
  • How dose a greenhouse allow plants to be grown in the cold winter months?
    7·2 answers
  • Answerr fasttt pleaseee lets see who can answer
    13·1 answer
  • If 0.590 moles of a gas are found in a 9.25 L container at 1.27 atm, what is the temperature?
    14·1 answer
  • If you have 1.5 grams of silver nitrate, how many grams of silver could<br> you produce?
    15·1 answer
  • If the reaction of 5.87 moles of potassium with excess hydrobromic acid was able to produce 2.49 mol H2, what is the percent yie
    15·1 answer
  • What is occurring in the image below?
    12·1 answer
  • For each of the following, give the sublevel designation, the allowable ml values, and the number of orbitals:
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!